Question

Write the expression without radicals, using only positive exponents

Answer 1

Answer:

$\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}$

Step-by-step explanation:

∵∛x = (x)^1/3

∴ $\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}$

So you can replace the radicals by fractional exponents

Answer 2

Answer:

The required expression is: $\sqrt[3]{a^2+b^2}=(a^2+b^2)^{\frac{1}{3}$.

Step-by-step explanation:

Consider the provided expression.

$\sqrt[3]{a^2+b^2}$

Now use the property: $\sqrt[n]{x+y}=(x+y)^{\frac{1}{n}}$

By using the above property the provided expression can be written as:

$\sqrt[3]{a^2+b^2}=(a^2+b^2)^{\frac{1}{3}$

Therefore, the required expression is: $\sqrt[3]{a^2+b^2}=(a^2+b^2)^{\frac{1}{3}$.