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Katena32 [7]
3 years ago
12

How can you write and solve equations involving rational number.

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:turn them into a fraction or decimal

Step-by-step explanation:

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What is the volume of a box measuring 8mm×10cm×5cm
notka56 [123]
The answer is 400 because u multiply 8 x 10= 80 x 5=400 
8 0
3 years ago
Read 2 more answers
Please help me for the love of God if i fail I have to repeat the class
Elena-2011 [213]

\theta is in quadrant I, so \cos\theta>0.

x is in quadrant II, so \sin x>0.

Recall that for any angle \alpha,

\sin^2\alpha+\cos^2\alpha=1

Then with the conditions determined above, we get

\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35

and

\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}

Now recall the compound angle formulas:

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta

\sin2\alpha=2\sin\alpha\cos\alpha

\cos2\alpha=\cos^2\alpha-\sin^2\alpha

as well as the definition of tangent:

\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}

Then

1. \sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}

2. \cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}

3. \tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}

4. \sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}

5. \cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}

6. \tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7

7. A bit more work required here. Recall the half-angle identities:

\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2

\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2

\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}

Because x is in quadrant II, we know that \dfrac x2 is in quadrant I. Specifically, we know \dfrac\pi2, so \dfrac\pi4. In this quadrant, we have \tan\dfrac x2>0, so

\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32

8. \sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}

6 0
3 years ago
What is the slope-intercept form of this equation?
kirill [66]

Answer:

y = -8x + 12

Step-by-step explanation:

Slope intercept form: y = mx + b

m ---> Slope   & b ----> y-intercept

8x + y = 12

Subtract 8x from both sides

y = -8x + 12

5 0
3 years ago
Find x and y…………….????????
emmasim [6.3K]

Answer:

let \:  \alpha  \: be \: the \: 45 \\  \tan( \alpha )  =  \frac{p}{b} \\  \tan(45)  =  \frac{x}{3 \sqrt{2} } \\ 1 =  \frac{x}{3 \sqrt{2} }  \\ x = 3 \sqrt{2}  \\ by \: using \: pythagoras \: therom \\  {y}^{2}  =  {3 \sqrt{2} }^{2}  +  {3 \sqrt{2} }^{2}   \\ {y}^{2}  = 18 + 18 \\ y =  \sqrt{36}  \\ y = 6

Step-by-step explanation:

hope this will help you

8 0
2 years ago
Can someone please help me, I'm stuck
mylen [45]
Continue the slop until it hits the y axis and that point will be your y intercept
4 0
3 years ago
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