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AleksAgata [21]
3 years ago
12

For the equation x^2+3x+j=0 , find all the values of j such that the equation has two real number solutions. Show your work.

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0
Use quadrratic equation discriminant
for
ax²+bx+c=0

if b²-4ac is the discriminant

if it is greater than 0, then it has 2 real number solutions
if it is equal to 0 then it has 1 real number solution
if it is less than 0 then it has 0 real number solutions

so

1x²+3x+j=0
b²-4ac=3²-4(1)(j)
9-4j
to have it have a real number solution, it must be greater than 0
9-4j>0
9>4j
9/4>j

j<9/4 is the solution area
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Answer:

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8 0
3 years ago
A card is drawn from a deck of 10 cards numbered 1 through 10 and a number cube is rolled. Find each probability.
Helen [10]

Answer:

1. P (10 and 3) = 1/10 * 1*6 = 1/60.

2. P (two even numbers)  = 5/10 * 3/6 = 15/60 = 1/4.

3. P (two prime numbers)  = 4/10 * 3/6 = 12/60 = 1/5.

4. P (9 and an odd number)  = 1/10 * 3/6 = 3/60 = 1/20.

5. P (two numbers less than 4)  = 3/10 * 3/6 = 9/60 = 3/20.

6. P (two numbers greater than 5) = 5/10 * 1/6 = 5/60 = 1/12.

Step-by-step explanation:

The card has the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.

The number cube has the numbers 1, 2, 3, 4, 5, and 6

In the deck of cards, 5 are odd and 5 are even. Also, there are 4 prime numbers in the deck. Also, there are 3 even and 3 odd numbers on the number cube. Also, there are 3 prime numbers cube. Therefore,

P(Selecting any card from the deck) = 1/10.

P(Any number is rolled on the dice) = 1/6.

Assume that probability of the cards and the cube are independent. So the probabilities can be calculated.

1. P (10 and 3) = 1/10 * 1*6 = 1/60.

2. P (two even numbers)  = 5/10 * 3/6 = 15/60 = 1/4.

3. P (two prime numbers)  = 4/10 * 3/6 = 12/60 = 1/5.

4. P (9 and an odd number)  = 1/10 * 3/6 = 3/60 = 1/20.

5. P (two numbers less than 4)  = 3/10 * 3/6 = 9/60 = 3/20.

6. P (two numbers greater than 5) = 5/10 * 1/6 = 5/60 = 1/12.

So the probabilities have been mentioned!!!

3 0
3 years ago
Select the correct answer.<br> Rewrite the following equation as a function of x.
ivolga24 [154]

Option B:

${f(x)}=9280-20x

Solution:

$\frac{1}{16} x+\frac{1}{320} y-29=0

$\frac{1}{16} x+\frac{1}{320} y-\frac{29}{1} =0

Take LCM of the denominators and Make the denominators same.

LCM of 16, 320, 1 = 320

$\frac{1\times20}{16\times20} x+\frac{1}{320} y-\frac{29\times 320}{1\times 320} =0

$\frac{20}{320} x+\frac{1}{320} y-\frac{9280}{320} =0

All the denominators are same, so you can write in one fraction.

$\frac{20x+y-9280}{320}=0

Do cross multiplication.

${20x+y-9280}=0\times 320

${20x+y-9280}=0

Add 9280 on both sides of the equation.

${20x+y}=9280

Subtract 20x on both sides of the equation.

${y}=9280-20x

Let y = f(x).

${f(x)}=9280-20x

Hence Option B is the correct answer.

6 0
4 years ago
A movie theater sells adult tickets for $6 each. Senior citizens receive a discount of $3. One evening the theater sold 400 tick
Andrej [43]

Answer:

Number of senior citizen tickets sold= 110

Number of adults tickets sold= 290

Step-by-step explanation:

<u>First, we need to establish a system of equations:</u>

x= number of adults tickets

y= number of senior citizen tickets

x + y= 400

6x + 3y= 2,070

<u>Now, we isolate x in one equation and substitute the value in the other:</u>

x= 400 - y

6*(400 - y) + 3y = 2,070

2,400 - 6y + 3y = 2,070

330 = 3y

110 = y

Number of senior citizen tickets sold= 110

Number of adults tickets sold= 290

<u>Prove:</u>

290 + 110= 400

6*290 + 3*110= 2,070

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Answer:

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Step-by-step explanation:

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