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katrin2010 [14]
3 years ago
11

the total cost of the trio is $600 what is the compatable number to estimate the total cost of the field trip

Mathematics
1 answer:
saveliy_v [14]3 years ago
3 0
Are there any other things that cost money that are in the equation?
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Jordan has $40 to spend at the yard sale. He buys 6 books for $2 each. He would like to spend the rest of his money on model car
Deffense [45]

Answer:

He can buy 4 model cars

Step-by-step explanation:

∵ His total money = the cost of books + the cost of model cars

∵ He buys 6 books and the price of each book is $2

∵ The cost of each model car is $7 , let the number of model cars is c

∵ He has $40

∴ 6 × 2 + 7 × c = 40

∴12 + 7c = 40

∴ 7c = 40 - 12 = 28

∴ c = 28/7 = 4

∴ He can buy 4 model cars

5 0
3 years ago
What is the answer to<br><br>6 1/4-3 5/8
german

Answer:

9 7/8

Step-by-step explanation:

solution by separating parts:

1) rewrite equation with parts separated

= 6 +1/4 + 3 + 5/8

2) solve whole number parts

6 + 3 = 9

3) solve fraction parts

1/4 + 5/8 = ?

- find the LCD of 1/4 and 5/8 and rewrite to solve

LCD = 8

2/8 + 5/8 = 7/8

combining the whole and fraction parts:

9 + 7/8 = 9 7/8

3 0
3 years ago
Find a rate and unit rate. $7.96 for 5 pounds of coffee.
Gwar [14]
The unit rate is $1.59 per pound of coffee
6 0
3 years ago
For the ordered pair, give three other ordered pairs with θ between −360° and 360° that name the same point.
FinnZ [79.3K]
<h2>Answer:(357^{0},330^{0}),(-3^{0},-30^{0}),(357^{0},-30^{0})</h2>

Step-by-step explanation:

For a ordered pair (\alpha ,\beta ),(\alpha -2n_{1}\pi ,\beta -2n_{2}\pi ) represents the same point in the cartesian plane where n_{1} and n_{2} are any integers.

Given point is (-3^{0},330^{0})

Taking n_{1}=-1,n_{2}=0,

(357^{0},330^{0})

Taking n_{1}=0,n_{2}=1,

(-3^{0},-30^{0})

Taking n_{1}=-1,n_{2}=-1,

(357^{0},-30^{0})

3 0
3 years ago
A card is drawn from a standard deck. Find the probability of drawing a heart or a 7.
Mazyrski [523]
<h3>Answer:   4/13</h3>

=======================================================

Explanation:

There are A = 13 hearts and B = 4 copies of "7"

The count A+B = 13+4 = 17 may seem like it's the count of hearts or "7" cards, but we're double counting the 7 of hearts. So the true count is actually 17-1 = 16

There are 16 cards we want (either a heart or a "7") out of 52 total. Therefore, the probability is 16/52 = (4*4)/(4*13) = 4/13

6 0
3 years ago
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