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tekilochka [14]
3 years ago
11

What is the common difference or common ratio of the sequence 2,5,8,11...? A. 1 B. 3 C. 5 D. 7

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0

\huge{\text{Hey there!}}

\huge\text{We could use the word {difference} in this equation}

\huge\text{The\ difference usually means subtract in math}} \huge\text{terms!}

\huge{\text{So, we subtract the terms to find your answer!}}

\huge\text{5 - 2 = 3. So we know that 3 could be a possible} \huge\text{answer.}

\huge\text{11 - 8 = 3 }

\huge\rightarrow\text{8 - 5 = 3}

\huge\text{The ratio difference = 3!}

\boxed{\boxed{\huge{\text{Answer: B. 3}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:}

RUDIKE [14]3 years ago
5 0

Answer:

B. 3

Step-by-step explanation:

A common difference in an arithmetic sequence is the value the terms in the sequence vary from one to another.You can find one term to another by adding or subtracting the common difference.

In this case, the terms are 2,5,8,11,.....

From the first term to the second term, the difference is, 5-2=3

From the second term to the third term, the difference is, 8-5=3

From the third term to the fourth term the difference is=11-8=3

Hence the common difference in this arithmetic sequence is 3

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Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

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Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

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The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

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