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Igoryamba
3 years ago
8

I'm completely lost?

Mathematics
2 answers:
damaskus [11]3 years ago
5 0
5.6* 10^3
5.6* (1,000)=5,600

1.3* 10^4
1.3* (10,000)=13,000
13,000-5,600=7,400
Liverpool had a greater population by 7,400 people.
aliya0001 [1]3 years ago
4 0
13000-5600=7400...that's about it, just multiply then subtract
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Mike watches how the pendulum swings in his clock. He notices that it swings 1 time every 2 seconds. How long will it take to sw
frosja888 [35]

Answer: 10 seconds

Step-by-step explanation: The time it takes is exactly double its swing. 5 times 2 = 10

4 0
3 years ago
Write the third missing congruent statement that will allow us to prove the triangles congruent by SAS.
musickatia [10]

Answer:

LOOK AT YOUR ANSWER IN PICTURE

8 0
3 years ago
Write a 4 -digit number that is divisible by both 5 and 9
vodomira [7]
4500 is both divisible by 5 and 9
4500/9=500
4500/5=900
6 0
3 years ago
Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi
il63 [147K]

Answer:

The formula to generate 70% confidence interval is: [\overline{x} - 0.013, \overline{x} + 0.013], in which \overline{x}  is the sample mean.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.7}{2} = 0.15

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.15 = 0.85, so Z = 1.037.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that \sigma = 0.04.

Sample of 10 birds:

This means that n = 10.

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

M = 1.037\frac{0.04}{\sqrt{10}}

M = 0.013

The lower end of the interval is the sample mean of \overline{x} subtracted by M.

The upper end of the interval is the sample mean of \overline{x} added to M.

Then, the formula to generate 70% confidence interval is: [\overline{x} - 0.013, \overline{x} + 0.013], in which \overline{x}  is the sample mean.

8 0
3 years ago
Explain why is 1/5 bigger than 0.15
Nitella [24]
1/5 is greater because it equals 0.2

0.2 has an imaginary 0 at the end, to make it 0.20

.20 > 0.15

Therefore, 1/5 is greater than 0.15
8 0
3 years ago
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