Answer:
$12
Step-by-step explanation:
assuming that the cost of delivery is constant irrespective of the number ordered
Let the cost of sandwich be x
First office
$33=4x+c where c is the cost of delivery
Second office
$61=8x+c
These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain
4x=28
Therefore, x=28/4=7
The cost of delivery is 33-(4*7)=33-28=5
Therefore, one sandwich plus delivery costs 7+5=$12
Answer:
<em>B) -7x + 7y = -49</em>
Step-by-step explanation:
This is a y=x plot/line shifted by 7 units.
This can also be verified plugging in the values of x=0,y=-7 and x=7,y=0. The only equation which satisfies these points in Equation B. These points have been chosen as they're the intercepts of this plot.
The linear function that models the situation is given by:

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A linear function for the cost C of taking care of p puppies has the following format:

In which:
- C(0) is the fixed cost.
- a is the slope, which is the cost per puppy.
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- With 6 puppies, it costs $172. With 10 puppies, it costs $220. The slope is given by the <u>change in the output(cost) divided by the change in the input(number of puppies)</u>, thus:

Thus:

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The cost of $172 with 6 puppies means that when p = 6, C = 172, and we use this to find C(0).




Thus, the linear model is:

A similar problem is given at brainly.com/question/16302622