1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eva8 [605]
3 years ago
8

HELP PLEASE 40 POINTS The graph shows the prices of different numbers of bushels of corn at a store in the current year. The tab

le shows the prices of different numbers of bushels of corn at the same store in the previous year. A graph shows Number of Bushels on x-axis and Price of Corn in dollars on y-axis. The x-axis scale is shown from 0 to 21 at increments of 3, and the y-axis scale is shown from 0 to 168 at increments of 24. A straight line joins the ordered pairs 3, 24 and 6, 48 and 9, 72 and 12, 96 and 15, 120 and 18, 144. Previous Year Number of Bushels Price of Corn (dollars) 3 21 6 42 9 63 12 84 Part A: Describe in words how you can find the rate of change of a bushel of corn in the current year, and find the value. Part B: How many dollars more is the price of a bushel of corn in the current year than the price of a bushel of corn in the previous year? Show your work. AND IT IS NOT QUESTION AND ANSWER PLEASE LOOK AT THE GRAPH AND READ THE PARAGRAPH

Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0

Answer:

Part A: 8 dollars/brushel

Part B: 1 dollar/brushel

Step-by-step explanation:

Without reading the question you can already conclude that this is a linear equation. Also, we can easily get the linear function:

f(x)=8x

Part A: Describe in words how you can find the rate of change of a bushel of corn in the current year, and find the value.

We know that a linear function has a constant rate of change, and that is called SLOPE.

In order to calculate the slope of the linear function:

$m=\frac{\Delta y}{\Delta x} = \frac{y_{2}- y_{1}}{x_{2}-x_{1}}= \frac{48-24}{6-3}= \frac{24}{3} = 8$

<u>Therefore, </u><u>the rate of change of a bushel of corn in the current year is 8</u>

<u></u>

Part B: How many dollars more is the price of a bushel of corn in the current year than the price of a bushel of corn in the previous year? Show your work.

<u>Previous Year Number of Bushels Price of Corn (dollars)</u>

Ordered pairs:

(3, 21); (6, 42); (9, 63); (12, 84)

Let's calculate the slope again.

$m=\frac{\Delta y}{\Delta x} = \frac{y_{2}- y_{1}}{x_{2}-x_{1}}= \frac{42-21}{6-3}= \frac{21}{3} = 7$

<u>The difference is  1 dollar/brushel.</u>

Vesna [10]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

Part A

Since the lines goes through the point (0,0) the graph is proportional. We can find the rate of change by take the price of corn and dividing by the number of bushels

24/3 = 8 dollars/ bushel

Part B

Previous Year Number of Bushels Price of Corn (dollars)

                                                  3 21

                                                 6 42

                                                  9 63

                                                 12 84

We can find the rate of change for the previous year by using the slope formula

m = (y2-y1)/(x2-x1)

m = (84-63)/(12-9)

    =21 / 3  

    = 7

The previous year was 7 dollars per bushel

The increase was 8-7 = 1 dollar per bushel

You might be interested in
Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
4 years ago
If the diagonals of a quadrilateral divide each other proportionally then it is a​
Artist 52 [7]

Answer:

Step-by-step explanation:

trapezium

<h2>If the diagonals of a quadrilateral divide each other proportionally, then prove that the quadrilateral is a trapezium.</h2>
3 0
3 years ago
Could you please explain it?
Troyanec [42]
Hello,
there are some words that I could not read. But:
I support evements are independants.
p(s)=0.2
p(l)=1-0.2=0.8 l=lose

1)0.8*0.2=0.16

2) 0.8²*0.2=0.128

3) 0.8^3*0.2=0.1024

4) 0.2*0.8^(n-1)

6 0
4 years ago
Consider the sequence 6, 11, 16, 21 . . . . What is the 50th term in this sequence?
Damm [24]

Answer:

251

Step-by-step explanation:

Tn=5n+1

e.g.T1=5(1)+1

=6

e.g.T2=5(2)+1

=11

e.g.T3=5(3)+1

=16

e.g.T4=5(4)+1

=21

Answer:T50=5(50)+1

=251

5 0
3 years ago
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
4 years ago
Other questions:
  • Lillianne made 6 out of every 10 baskets she attempted during basketball practice. If she attempted to make 25 baskets, how many
    8·1 answer
  • Find the value of x <br> A. 44<br> B. 34<br> C. 56<br> D. 22<br><br> SHOW ALL WORK
    15·2 answers
  • Slove the following exponential decay function for t when x= 5. Round to the nearest hundredth.
    7·1 answer
  • Determine the product of 800.5 x (2x10^6)
    7·1 answer
  • Tiana would like to buy cone-shaped hats for her birthday party. She wants hats with the largest volume, since they look bigger.
    7·2 answers
  • Find the radius of a circle that has an area of 12.56 cm².
    10·1 answer
  • A. ∠2<br><br> B.∠5<br><br> C.∠4<br><br> D.∠3
    9·1 answer
  • If i get paid 7$ plus 15% how much is that
    14·1 answer
  • Solve these equations. Show solutions on a number line.<br><br> |x+8|=x+8<br><br>​
    9·1 answer
  • Why is y = 3.5 x proportional
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!