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Vlad1618 [11]
3 years ago
6

Write in standard form. Three hundred thousand and forty five

Mathematics
2 answers:
Airida [17]3 years ago
8 0
300,045 is the answer!!
Lapatulllka [165]3 years ago
4 0

Answer:

300,045

plz mark brainliest

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katrin [286]

C' ( 0, 3)

A' ( 2 , 1)

C'A' = CA

C'A' = √(2^2 + 2^2) = √8 = 2√2

C'A' = CA = 2√2

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Jaylen brought j crackers and combined them with Marvin m crackers . They then split the crackers in to 7 friends type an algebr
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J+M=T/7

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J = Jaylens crackers
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Identify the range of the following numbers 8,2,10,4,4,6
Galina-37 [17]
10 - 2 = 8 

Biggest number subtracted by the smallest number is range.
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4 years ago
1. Jonah has $75 in a savings account and is putting $7 every week in the account.
GaryK [48]

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Step-by-step explanation:

6 0
3 years ago
Find the sum of the first 9 terms in the following geometric series. 64+32+16+
Dafna11 [192]

Answer:

The sum of the first 9 terms in the geometric series is 127.75

Step-by-step explanation:

In the geometric series, there is a constant ratio between each two consecutive numbers

<u>Examples:</u>

5,  10,  20,  40,  80,  ………………………. (×2)

5000,  1000,  200,  40,  …………………………(÷5)

General term (nth term) of a Geometric series is

<em>a1</em> = <em>a</em>, <em>a2</em> = <em>ar</em>, <em>a3</em> = <em>ar</em>²,  <em>a4</em> = <em>ar</em>³, ..........

an=ar^{n-1}, where

<em>a </em>is the first term

r is the constant ratio between each two consecutive terms

The sum of the first <em>n</em> terms of a Geometric series is calculated by this rule

Sn=\frac{a(1-r^{n})}{1-r}

Let us solve the question

∵ The geometric series is 64, 32, 16, .......................

∴ <em>a </em>= 64

∴ <em>r </em>= 32 ÷ 64 = 0.5

→ We need to find the sum of the first 9 terms

∴ <em>n</em> = 9

→ Substitute these values on the formula of the sum above

∴ S9=\frac{64(1-0.5^{9})}{1-0.5}

→ use the calculator to find the answer

∴ <em>S</em>9 = 127.75

 ∴ The sum of the first 9 terms in the geometric series is 127.75

7 0
3 years ago
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