Answer:
Step-by-step explanation:
<u>Identity</u>
<u>Simplifying the LHS (Left Hand Side)</u>
- (√24-√k)(√24+√k)
- (√24)² - (√k)²
- 24 - k
<u>Equating to the RHS</u>
- 24 - k = 5
- k = 24 - 5
- <u>k = 19</u>
When you are multiplying exponents with the same base, you can add the exponents. This is represented as:
In our case we are multiplying exponents with the same base 8 and exponents -7 and 5. The sum of -7 and 5 is -2, so our answer is 
.
The reliability of a two-component product if the components are in parallel is 0.99.
In this question,
The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.
A system contains two components that are arranged in parallel, they are 0.95 and 0.80.
Therefore the system reliability can be calculated as follows
⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )
⇒ 1 - (0.05 × 0.20)
⇒ 1 - 0.01
⇒ 0.99
Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.
Learn more about reliability of components here
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X= -5/8-5/8√33 or x= -5/8+5/8 √<span>33</span>
Answer:
-28
Step-by-step explanation:
Remember the order of operations: pemdas (<u>p</u>arenthesis, <u>e</u>xponent, <u>m</u>ultiply, <u>d</u>ivide, <u>a</u>dd, <u>s</u>ubtract). Just simplify the expression.
22 - 53 + 3
(22-53) + 3
-31 + 3
-28
