Answer:
$3,000 invested at 6%
$7,000 invested at 10%
Step-by-step explanation:
Maria had total $10,000 to invest.
Let x be the amount that Maria invested initially at 6% interest rate.
0.06x
Then she invested the remaining amount at 10% interest rate.
0.10(10,000 - x)
She received a total of $880 in interest.
0.06x + 0.10(10,000 - x) = 880
0.06x + 1000 - 0.10x = 880
-0.04x = 880 - 1000
-0.04x = -120
0.04x = 120
x = 120/0.04
x = $3,000
This is the amount that Maria invested initially at 6% interest rate.
The remaining amount is
10,000 - 3,000
$7,000
This is the remaining amount that she invested at 10% interest rate.
Answer:
56
Step-by-step explanation:
Just substitute 7 for p in the expression 9p - 7: 9(7) - 7 = 56
the answer i got was 50,000
if its not right i can try to figure it out again
A=7,500×(1+0.06÷4)^(4×2)
A=8,448.69
Interest earned=8,448.69−7,500
Interest earned=948.69
Hi!
So really focus on the fact that he started at $230, and then added an amount of money which we'll call x, which made his total equal $599.
Take the parts I put in bold, and write the equation.
$230 + x = $599
Now we need to find x.
Whatever we do to the equation, we do it to both sides.
Our goal is to isolate x on one side.
Subtract 230 from both sides.
$230 - $230 + x = $599 - $230
x = $369
The answer is A. $230 + x = $599 x = $369
Hope this helps! :)
-Peredhel
