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3 years ago

Will mark as brainliest!!

Mathematics

2 answers:

Murrr4er [49]3 years ago

5 0

Answer:

Step-by-step explanation:

fredd [130]3 years ago

3 0

14 feet I think..........................

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What's 45 out of 58 in percentage?

Vladimir [108]

$For \ any \ percentage \ you \ just \ take \ the \ number, \ here \ 45, \\ divide \ by \ the\ number \ here\ 58,\ and \ multiply \ by \ 100 \ \%. \\\\ \frac{45}{58}\cdot 100 \ \%= 0,7758 \cdot 100 \ \%=77,58 \ \% \approx 78 \ \%$

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3 years ago

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Evaluate the numericial expression (32 - 20) ÷ 4

SashulF [63]

Answer:

Step-by-step explanation:

(32-20)÷4

solve perentisis first

(12)÷4

now divide

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2 years ago

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What is the distance between (-3,5) (7,5)

Firlakuza [10]

Answer:

10 units

Step-by-step explanation:

use distance formula: d = square root of the difference of the y-values minus the difference of the x-values

d = $\sqrt{(5-5)^2+(7--3)^2}$

d = $\sqrt{(0)^2+(10)^2}$

d = $\sqrt{100}$

d = 10 units

4 0

3 years ago

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Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar

bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\$

A. P(x=6)

$P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\$

B. P(x≥10)

$P(x\geq10)=1-P(x$

$P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\$

$P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\$