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aleksklad [387]
3 years ago
12

Can you please help me with this ? I thought I understood today but still not on target with it .

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0
1) B
This is because the x value = quarts and the y value = pints, there are 3 quarts and 6 pints.

2) A
Its going up 2 every time in the y axis, rise over run= 2 over 1

3) C 
They are both at 0
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30 POINTS. please do not guess, i will make sure you get reported for it,
Greeley [361]

Answer:

34

Step-by-step explanation:

23+15;

175-100

=75

":)

don't report this is the correct answer

5 0
3 years ago
An urn contains ten chips. An unknown number of chips are white' the others are red. We wish to test:
Olin [163]

Answer:

Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips  are white. Then,

a) Find α

α = P (reject H0 | H0 is true) = P (X ≥ 2|E)  

  = P (X = 2|E) + P (X = 3|E),    

We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution

  =  (5C2 * 5C1)/10C3  +  (5C3 * 5C0)/10C3

  =  0.5

So,  α = 0.5

b) Find β

i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)

β = P (accept H0 | E1) = P (X ≤ 1|E1)

  =  (6C0 * 4C3)/10C3  +  (6C1 * 4C2)/10C3

 = 1/3

 = 0.333

So, β = 0.333

i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)

β = P (accept H0 | E2) = P (X ≤ 1|E2)

  =  (7C0 * 3C3)/10C3  +  (7C1 * 3C2)/10C3

 = 11/60

 = 0.183

So, β = 0.183

5 0
4 years ago
In which quadrant does the given point lies??? (3,-2)
trapecia [35]
Quadrant 4 .
    make a graph and plot the point. The upper right square is quadrant 1, the upper left is 2, lower left is 3, and lower right if 4. so when you plot (3, -2) it lies in the lower right. 
6 0
4 years ago
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

3 0
3 years ago
Read 2 more answers
Which type of graph is show above?
Cerrena [4.2K]

Answer:

B) Exponential graph

Step-by-step explanation:

6 0
3 years ago
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