Hello,
y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x
x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++
y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>
Answer:
Step-by-step explanation:
Rewrite this as

Knowing that i-squared = -1:

Both i-squared and 100 are perfect squares, so this simplifies to
±10i
-5^7/-5^2=5^7/5^2= 5^(7-2)=5^5 this is the answer
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5x^2+3xy-25x-15y= 5x^2-25x+3xy-15y=
5x(x-5)+3y(x-5)=
= (x-5)(5x+3y)