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creativ13 [48]
3 years ago
6

For the vectors u= (1, 3, 2) and v=(2, 0, 3)​, evaluate the following expressions.

Mathematics
1 answer:
Ratling [72]3 years ago
7 0

Answer:

a) 4u + 2v = (8, 12, 14)

b) 2u - v = (0, 6, 1)

c) |u + 4v| = 16.9

Step-by-step explanation:

When we add/subtract vectors, we add/subtract their components. For example

a = (a1,a2,a3)

b = (b1,b2,b3)

a+b = (a1 + b1, a2 + b2, a3 + b3)

|a| is the modulus of vector a, given by

|a| = \sqrt{a1^{2} + a2^{2} + a3^{3}}

In this problem, we have that:

u = (1,3,2)

v = (2,0,3)

(a) 4u+2v

4u = 4(1,3,2) = (4,12,8)

2v = 2(2,0,3) = (4,0,6)

4u + 2v = (8, 12, 14)

(b) 2u-v

2u = 2(1,3,2) = (2,6,4)

v = (2,0,3)

2u - v = (0, 6, 1)

(c) |u + 4v|

u = (1,3,2)

4v = 4(2,0,3) = (8,0,12)

u + 4v = (9,3,14)

|u + 4v| = \sqrt{9^{2} + 3^{2} + 14^{2}} = 16.9

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DedPeter [7]

Answer:

The probability of getting a pair of red socks is 0.322

Step-by-step explanation:

According to the given data we have that A drawer contains 11 identical red socks and 8 identical black socks, hence, the total number of socks is 19, therefore, in order to calculate the probability of getting a pair of red socks we would have to use the following formula:

probability of getting a pair of red socks=11C2/19C2

probability of getting a pair of red socks=55/171

probability of getting a pair of red socks=0.322

The probability of getting a pair of red socks is 0.322

4 0
3 years ago
Help please :( points !
mars1129 [50]
Answer: 2/5

Explanation: 10+8+12 = 30 12/30 = .4 .4 = 2/5
4 0
3 years ago
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Help due soon <br> find the area using 3.14 for π<br> round to the nearest Hundredth if you have too
andrey2020 [161]

Answer:

Circumference is about 185.26 cm.

Area is about 2732.585 cm^{2}

Step-by-step explanation:

Circumference = 2πr

2 x 3.14 x 29.5 = 185.26

Area of a circle = πr^{2}

3.14 x 29.5 x 29.5 = 2732.585

7 0
3 years ago
Someone please help me quick I've been stuck on this problem for 2 hours and my assignment is due at 10:30pm.
astraxan [27]

Answer:

419.5 ft of BX cable

step-by-step explanation:

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The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

8 0
3 years ago
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