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Vikki [24]
3 years ago
8

Solve this dont post irrelavent answers ​

Mathematics
1 answer:
slava [35]3 years ago
4 0

Answer:

a=3

Step-by-step explanation:

p(x)=x^2-x-6 and f(x)=x^2+3x-18

they have a common factor x=a

so, when they are devided by x-a leave 0 as the remainder ( by remainder theorem)

p(a) =0

f(a)=0

SO, p(a) =f(a)

a^2-a-6=a^2+3a-18

a^2-a^-a-3a= -18+6

-4a= - 12

a=3

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Answer:

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Step-by-step explanation:

7 0
3 years ago
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Find sec A and cot B exactly if a = 8 and b = 7.
Shtirlitz [24]

Answer:

sec A= 1.01 and cot B =8.25

Step-by-step explanation:

Given :

sec A and cotB if a =8 and b=7

Now,

=sec A=\frac{1}{cos A} \\\\\frac{1}{cos 8} \\\\\frac{1}{0.99} \\1.01

and

cot B=\frac{cosB}{sin B} \\cotB=\frac{cos 7}{sin7} \\cot B =\frac{0.99}{0.12} \\cot B =8.25

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8 0
3 years ago
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Tamiku [17]
Jus look and the answer above
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3 years ago
F left parenthesis x right parenthesis equals 9 x cubed plus 2 x squared minus 5 x plus 4 and g left parenthesis x right parenth
Jet001 [13]
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Each of these is divisible by 2, and each has an x, so we factor those out:
2x(                        )

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2x²/2x=x:
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3 0
3 years ago
Can someone help me
Sever21 [200]
The correct answer is x^2-6x+8
4 0
2 years ago
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