You have to calculate the median and which the numbers all
<span>We have a right angled triangle with an opposite of 300.5 ft. (306 - 5.5) and an adjacent of 400 ft. Recalling SOH CAH TOA, tanθ = O/A.
tan(θ) = 300.5/400.
θ = tan^-1(300.5/400).
θ = 36.9°.</span>
The slope of the line that passes through the pair of point (5, 7), (2, 1) is 2
<em><u>Solution:</u></em>
Given that line that passes through the pair of point (5, 7), (2, 1)
To find: slope of the line
<em><u>The slope of line is given as:</u></em>
For a line passing through two points and slope is given as:
Here in this problem,
<em><u>Substituting the values in above formula,</u></em>
Thus the slope of given line is 2
Through 1-3 There should be a line that goes from (0,0) to (3,15) as they did work for three hours. The rest seems fine.
For the answer to the question above asking<span> what is the measure of an acute base angle of the trapezoid?
</span>n acute base angle of the trapezoid would be the same as the triangle.
<span>subtract 34º from 180º, then divide by 2. </span>
<span>(180 - 34)/2 = 73º
</span>I hope my answer helped you.