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exis [7]
3 years ago
6

(6x^3+9x-8)+(5x-9x^2+7

Mathematics
2 answers:
irinina [24]3 years ago
6 0
Add like terms
I'm assuming that you forgot to put the parenthasees at the end

so exg
4x+8x=12x
2x^2+3x^2=5x^2
3x^2+3x^3=3x^2+3x^3
group like tems
6x^3+9x-8+5x-9x^2+7
6x^3-9x^2+14x-1
Mars2501 [29]3 years ago
6 0
6x^3 + 9x -8 +5x -9x^2 +7
6x^3 - 9x^2 + 14x -1
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-30 = -16 + N what is he answer to this
marta [7]

Answer:

Step-by-step explanation:

To solve for the given variable N, we need to get N on one side of the equation by itself. To do so, we need to remove the -16 that is on the same side of the variable.

To get rid of the -16, we can add a 16 to that side of the equation since -16 + 16 = 0, which will get N by itself; however, if we add -16 to one side of the equation, we must add it to both sides of the equation:

-30 + 16 = -16 + 16 + N

-14 = N

4 0
3 years ago
Keelin’s hourly rate went from $9.50 per hour to $10.25 per hour. What is the percent increase?
bazaltina [42]

Answer:

.75 would be your answer to your question!

I hope this really answered your question and i'm really happy to help!

Step-by-step explanation:

So you would take the $9.50 + .75 and you will get the answer $10.25

3 0
3 years ago
What is the name of this polygon? rectangle square trapezoid rhombus A quadrilateral. Each side has one tick mark.
julsineya [31]
I think it’s a rhombus.
6 0
3 years ago
Read 2 more answers
What is the surface area of the prism?
Harman [31]
Area of lower rect + area of upper + 4 * sides rect areas

lower = upper rect

2 * rect1 + 4 * rect2

Area = 2 * 6 * 11 + 2 * 11 * 9 + 2 * 9 * 6 = 438 ft^2

or simply just take 2 ( and multiply each two sides.

5 0
3 years ago
A log is 20 m long, correct to the nearest metre.
Marat540 [252]

Answer:

222 fence posts

Step-by-step explanation:

Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct  to the nearest 10 centimetres, there can be x fence posts 90 cm long.

So, we have x × 90 cm = 20 m

x × 0.9 m = 20 m

x = 20 m/0.9 m

x = 222.22

x ≅ 222 fence posts

So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.

4 0
3 years ago
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