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user100 [1]
3 years ago
14

Which of the following represents the best way to calculate area of shaded region?

Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

D: Calculate the area of one of the two overlapping sectors, then subtract the area of its triangle find the area of the segment, and multiply this are by two.

Step-by-step explanation:

I just missed this question and this is the correct answer

sattari [20]3 years ago
3 0
The correct answer for the exercirse shown in the figure attached is the first option, which is: Calculate the area of the circle A and circle B and calculate the difference.

 To calculate the area of the circle A and the circle B, you must apply the formula for calculate the area of a circle, which is shown below:

 A=πr²

 A is the area of the circle.
 r is the radius of the circle.

 To calculate the difference, you only have to substract the result of the area of the circle A and the area od the circle B:

 At=Aa-Ab
You might be interested in
Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
When given the equation y = 3/4x − 6 , Find the x intercept and y intercept.
STALIN [3.7K]

Answer:

the y-intercept is (0,-6)

the x-intercept is (8,0)

Step-by-step explanation:

<em>Solving for the y-intercept:</em>

Since the equation 'y=3/4x - 6' is in the 'y=mx + c' form (where m is the slope and c is the y-intercept):

3/4 is m (which is the slope)

-6 is c (which is the y-intercept)

<em>Solving for the x-intercept:</em>

When the line intersects with the x-axis, the y-value is 0. Hence, the coordinate is (x,0). Substituting this into 'y=3/4x - 6':

0 = 3/4x - 6

3/4x - 6 + 6 = 6

3/4x = 6

x = 4/3 * 6

= 8

Hence,

the y-intercept is (0,-6)

the x-intercept is (8,0)

<em>Hope this helps and be sure to have a wonderful time ahead at Brainly! :D</em>

7 0
2 years ago
List all sets that apply for 0.6
uranmaximum [27]

Answer:

i know

Step-by-step explanation:0.6

3 0
3 years ago
When angles are complementary the sum of their measures is 90 degrees. Two complementary angles have measured of 2x-10 degrees a
Vinvika [58]

56° and 34°

complementary angles sum to 90° thus

3x - 10 + 2x - 10 = 90

5x - 20 = 90

add 20 to both sides of the equation

5x = 90 + 20 = 110

divide both sides by 5

x = \frac{110}{5} = 22

angle 2x - 10 = (2 × 22) - 10 = 44 - 10 = 34° and

angle 3x - 10 = (3 × 22) - 10 = 66 - 10 = 56°


3 0
3 years ago
What are the center and the radius of the circle whose equation is (x-5)^2+(y+3)^2=16
Sindrei [870]

CENTER : ( 5, -3)

RADIUS : 4

5 0
3 years ago
Read 2 more answers
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