Find the zeros of the following polynomial x^2-2x+1

Mathematics

2 answers:

Mashcka [7]3 years ago

5 0

It factors to (x - 1)(x - 1)

the zeroes are ix = 1. Duplicity 2.

muminat3 years ago

4 0

If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.

So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.

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lukranit [14]

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Given - a rectangle with length 25 feet and perimeter 80 feet

To calculate - width of the rectangle

We know that ,

$\bold{Perimeter \: of \: rectangle = 2(l + b)} \\$

where b = width / breadth of rectangle

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substituting the values in the formula stated above ,

$\bold{80 = 2(25 + b)} \\ \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\ \\ \bold{\implies \: 25 + b = 40 }\\ \\ \bold{\implies \: b = 40 - 25 }\\ \\\bold{ \implies \: b = 15 \: feet}$