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Cloud [144]
3 years ago
6

Please help!! Thanks!

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

5)B 6)A 7)C are the answers I believe.

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You put $800 in a savings account. The account earns 4% simple interest per year.
nalin [4]

Answer:

A. 160

B. 960

Step-by-step explanation:

The interest earned after 5 years is the balance - the initial balance: 160

The balance is 800 * (1 + .04*5): 960

4 0
4 years ago
A copy machine produces 40 copies in 5 minutes. How many copies can 2 points the machine make in 30 minutes and how do you know?
slavikrds [6]

Answer:

240 copies

Step-by-step explanation:

40/5 to find how many copies a minute.

You get 8 copies a minute.

Multiply 8 copies by 30 minutes to get 240 copies

3 0
3 years ago
Factor over complex numbers 2x^4+36x^2+162
Darina [25.2K]

<u>Answer:</u>

Factor over complex numbers of 2 x^{4}+36 x^{2}+162 is 2(x+3 i)^{2}(x-3 i)^{2}

<u>Solution:  </u>

From question given that

2 x^{4}+36 x^{2}+162  → (1)

On substituting x^{2}=y in equation (1),

=2 y^{2}+36 y+162

Taking 2 as a common in above expression,

=2\left(y^{2}+18 y+81\right)

Rewrite the above expression,

=2\left[y^{2}+2(y)(9)+9^{2}\right]

=2(y+9)^{2}  \left[\text { Using }(a+b)^{2}=a^{2}+2 a b+b^{2}\right]

=2\left(x^{2}+9\right)^{2} \left[\text { since } y=x^{2}\right]

\left[\text { Using } a^{2}+b^{2}=(a+i b)(a-i b), \text { where } i=\sqrt{-1}\right]

=2[(x+3 i)(x-3 i)]^{2}

=2(x+3 i)^{2}(x-3 i)^{2}

Hence Factor over complex numbers of 2 x^{4}+36 x^{2}+162 is 2(x+3 i)^{2}(x-3 i)^{2}

7 0
4 years ago
Y = 3x - 1
lubasha [3.4K]

Answer:

no solution.

Step-by-step explanation:

given that, y = 3x-1

so,

in equation, 3x-y = 9

putting the value of y here,

3x-(3x-1) = 9

3x-3x+1 = 9

3x and 3x is cancelled.

hence, no solution

6 0
3 years ago
Help pls, i cant figure it out
sergeinik [125]
I don’t see a picture
8 0
3 years ago
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