x= 3+√5/4,3-√5/4
Step-by-step explanation:
1.In general, given ax^2+bx+c=0, there exists two solutions where:
x= -b+√b^2 - 4ac/2a, -b-√b^2-4ac/2a
2.In this case, a=4, b=-6 and c=1.
x=6+√(-6)^2-4×4/2×4, 6-√(-6)^2-4×4/2×4
3.Simplify.
x=6+2√5/8, 6-√5/8
4.Simplify solutions.
x=3+√5/4, 3-√5/4
-10/3+3/4
-40/12+9/12
-31/12
-2 7/12
AC＝AC (reason: reflexive property)
Step-by-step explanation:
Hope it helps you!
Answer:
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Step-by-step explanation:
