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3 years ago

13

Trevon spent 8 hours and 15 minutes at an amusement park yesterday. he spent 75% of the time at the park on rides. About how muc

h time did he spend in rides.

1 answer:

sammy [17]3 years ago

7 0

6 hours and 18 minutes

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Jaylynn was buying new mascara. She bought it on sale for $5.56. If the price represents a 20% discount from the original price,

Len [333]

X-0.20x=5.56
Solve for x
So the original price is
X=6.95

4 0

3 years ago

The leaning tower of Pisa currently "leans" at a 4 degree angle and has a vertical height of 55.86 meters. How tall was the lean

Marizza181 [45]

Answer:

56 meters.

Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

$\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

Upon substituting our given values we will get,

$\text{Cos (4)}=\frac{55.86}{h}$

$h=\frac{55.86}{\text{Cos (4)}}$

$h=\frac{55.86}{0.99756405026}$

$h=55.996\approx 56$

Therefore, the leaning tower was approximately 56 meters, when it was originally built.

6 0

3 years ago

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

3 years ago

Jerome solves the inequality y–2 ⩽ 9 in one step, writing y ⩽ 11 as the solution. What property best justifies the step he used

DedPeter [7]

The answer is b because he added 2

8 0

3 years ago

Please help if you know the answer.....

andre [41]

I’m not really sure but I would say c

8 0

3 years ago

Read 2 more answers