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3 years ago

Your part time job pays you $14/h. You work approximately 12 hours/week.

Mathematics

1 answer:

kirill115 [55]3 years ago

4 0

Answer:

BOX 1 = 672.00

(14 * 12 = 168

168 * 4 = $ 672 )

2. BOX 2 = 282.95

(Cell phone= $45 A MONTH

Eating outside = $50 A MONTH

12 .50 * 4 = 50 (4 WEEKS A MONTH )

Transportation = 131.2 A MONTH

32.80 * 4 = 131.2 (4 WEEKS A MONTH )

Movie = $16.75 A MONTH

Charity = $ 40 A MONTH

10 * 4 (4 WEEKS A MONTH )

 MONTHLY EXPENSE  = 45 + 50 + 131.2 + 16.75 + 40

 MONTHLY EXPENSE  = 282.95 )

3. BOX 3 = 389.05

Money that can be saved = Monthly income - Monthly expense

Money that can be saved = 672 - 282.95

= 389.05

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If a car goes around a turn too quickly, it can leave tracks that form an arc of a circle. By finding the radius of the circle,

Slav-nsk [51]

Answer:

155.7

Step-by-step explanation:

Use what you know.

Segment AC is 130 ft

Segment CD is 70ft

If you use the Pythagorean Theorem, in this case being = +

To find segment CE, you would do r-70

So, = +

= 16,900 + -140r + 4900

Add the -140r to the left side and then get rid of the two . Then Add 16,900 and 4900 together

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Divide 140 on each side.

Your final answer will be 155.7 (rounded to the nearest tenth)

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3 years ago

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WARRIOR [948]

For Henry: 4 out of 9 is equal to 4 divided by 9. That gives you approximately 0.444. Multiply that by 100 to get the percentage and you get 44.4%.

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3 years ago

Mick paid $2.94 in sales tax of an item that cost $42.00 before tax. At that rate, how much would he pay in sales tax for an ite

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3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

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3 years ago

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Answer:

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Step-by-step explanation:

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