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GenaCL600 [577]
3 years ago
9

Which equation can be used to determine the reference angle r if 7pi/12?

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

If we draw the given angle \frac{7\pi }{12}, the terminal side will be in second quadrant.

So the reference angle will be the angle between x axis and the terminal side of given angle.

For this, we have to subtract it from \pi

So the reference angle will be : \pi-\frac{7\pi}{12}

making common denominator

reference angle = \frac{12\pi}{12}-\frac{7\pi}{12}

reference angle = \frac{5\pi}{12}    :   Answer

Hope it will help :)

Daniel [21]3 years ago
4 0
7pi/12 > pi/2, This means it is in 2nd quadrant.
For angles in 2nd quadrant, subtract from pi to get reference angle.

pi - 7pi/12 = 5pi/12
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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

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A chemical refinery needs a vat. They want the vat to be a rectangular prism (with square bases) that has a maximum volume of 1,
Alex17521 [72]

Answer:

For least material to be used lengths of square base and sides = 10 units.

Step-by-step explanation:

Let the lengths of the square base and the sides = x feet, x feet and y feet

Area of the square base = x² feet

Volume of the rectangular prism = Area of the square base × Height

                                                      = x²y cubic feet

1000 = x²y

y = \frac{1000}{x^2} -------(1)

Material used in the prism = Surface area of the rectangular prism

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Here, h =  height of the prism

l = length of the base

w = Width of the base

Material to be used (S) = 2(xy + x² + xy) - Area of lid

                                  S = 2(x² + 2xy) - x²

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Now by substituting the value of y from equation (1),

S = x² + 2x(\frac{1000}{x^{2} })

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S' = 2x - \frac{2000}{x^{2} }

2x - \frac{2000}{x^{2} } = 0

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x³ = 1000

x = 10 feet

From equation (1),

y = \frac{1000}{(10)^2}

y = 10 feet

Therefore, for least amount of the material used lengths of square base and sides will be 10 feet.

7 0
3 years ago
A rectangle is 2.5 times as long as it is wide. Find the dimensions of the rectangle if it is perimeter is 56 cm.
antoniya [11.8K]
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or, 56 = 2(2.5 breadth + breadth)
or, 56 = 7*breadth
breadth = 56*7 = 8 cm
length = 2.5*8 = 20 cm
6 0
3 years ago
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