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3 years ago

How do switches and bridges learn where devices are located on a network?

Computers and Technology

1 answer:

leva [86]3 years ago

3 0

Not exactly sure but I think it's the MAC Address.

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Write a recursive method named binarySearch that accepts a sorted array of integers and an integer target value and uses a recur

djyliett [7]

Answer:

-1

Process finished with exit code 0

Explanation: see code bellow

public class BinarySearchRecursive {

public static int binarySearch(int[] a, int key) {

return binarySearchRecursiveHelper(a, key, 0, a.length - 1);

}

public static int binarySearchRecursiveHelper(int[] arr, int target, int start, int end) {

if (start > end) {

return -1;

}

int mid = (start + end) / 2;

if (arr[mid] == target) {

return mid;

} else if (target < arr[mid]) {

return binarySearchRecursiveHelper(arr, target, start, mid - 1);

} else {

return binarySearchRecursiveHelper(arr, target, mid + 1, end);

}

public static void main(String[] args) {

int[] a = {-4, 2, 7, 10, 15, 20, 22, 25, 30, 36, 42, 50, 56, 68, 85, 92, 103};

int index = binarySearch(a, 42); // 10

System.out.println(index);

index = binarySearch(a, 66); // -1

System.out.println(index);

}

6 0

3 years ago

During the boot process, the computer performs a quick self diagnostic then loads the operating system into memory.... IS THIS T

zlopas [31]

<span>The answer is False. During the boot process, the computer will perform a self-diagnostic, also known as a POST and load necessary drivers and programs that help the computer and devices communicate.</span>

7 0

3 years ago

A direct-mapped cache holds 64KB of useful data (not including tag or control bits). Assuming that the block size is 32-byte and

Cerrena [4.2K]

Answer:

A) Number of bits for byte = 6 bits

B) number of bits for index = 17 bits

C) number of bits for tag = 15 bits

Explanation:

Given data :

cache size = 64 kB

block size = 32 -byte

block address = 32 -bit

number of blocks in cache memory

cache size / block size = 64 kb / 32 b = 2^11 hence the number of blocks in cache memory = 11 bits = block offset

A) Number of bits for byte

$log _{2} (6)^2$ = 6 bits

B) number of bits for index

block offset + byte number

= 11 + 6 = 17 bits

c ) number of bits for tag

= 32 - number of bits for index

= 32 - 17 = 15 bits

5 0

3 years ago

Methods used to change variables are called ______. equals accessors toString void mutators

Sindrei [870]

Look this up on Quizlet. Besure to check the question and the answers carefully by using "define + the vocabulary word" you think answers the question.

Here is the exact site: just copy it and search and click...

<span>AP Comp Sci Chapter 5</span>

6 0

3 years ago

Select the correct answer.

Crank

Answer:

Sensing elements.

Explanation:

Sensing elements are the device which connect channels feedback and return it to the control system input. There are many sensors used for feedback control such as Tachometer, Encoders, Accelerometers and rate gyroscopes.

3 0

3 years ago