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Dmitrij [34]
3 years ago
11

AB is tangent to circle O at B. what is the length of the radius r? Round to the nearest tenth. Look at image attached.

Mathematics
2 answers:
Alexxx [7]3 years ago
4 0
Check the picture below.

kompoz [17]3 years ago
3 0
OAB is a right triangle. Of this triangle, you know the hypothenuse (OA) and the longest leg (AB). You can find the radius, which is the shortest leg, by applying Pitagora.

r (OB) = √OA²-AB² = √9,8²-5² = √96,04-25 = √71,04 ≈ 8,4 (units?)

Answer D
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7 0
3 years ago
Read 2 more answers
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
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Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

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Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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