Ask question

Ask question

All categories

allochka39001 [22]

3 years ago

13

Si en una proporción geométrica continua, la media geométrica es 24 y la razón es 2/3 ¿Cuánto es la diferencia de los extremos?.

a)18 b)20 c)24 d)16 e)12

1 answer:

vaieri [72.5K]3 years ago

6 0

Yo creo que es C-24 de todos

You might be interested in

Write 16.66666666... as a fraction.

adoni [48]

The answer is 16 2/3 as explained above

3 0

3 years ago

If YZ= 55 millimeters, what would be the length of QR? Millimeters

rusak2 [61]

Answer:

<h2>30 mm</h2>

Step-by-step explanation:

<h3>Hope it help </h3>

6 0

2 years ago

-1/2y=1/2x+5 and y=2x+2

Anettt [7]

I assume this is the intersection of two lines, i.e. -1/2y is (-1/2)y. Please tell me if it's really -1/(2y).

(-1/2)y=(1/2)x+5

Multiplying both sides by -2

y = - x - 10

The other equation is

y = 2x + 2

We can equate them to find the meet

y = - x - 10 = 2x + 2

-3x = 12

x = -4

y = 2x + 2 = -6

Check: (-1/2)y=3, (1/2)x+5=3, equal, good

2x+2=2(-4)+2=-6=y, good

Answer: x=-4, y=-6

6 0

2 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

So

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

2 years ago

1/3 x = 1/6 write answer as a fraction

Andrews [41]

Step-by-step explanation:

1/3x=1/6

x/3=1/6

cross multiply

6x=3

divide both sides by 6

x=3/6

x=1/2

6 0

2 years ago

Read 2 more answers