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joja [24]
4 years ago
9

Please please help me!!!!!

Mathematics
1 answer:
N76 [4]4 years ago
6 0
The 4 marked x is 10 times greater than the 4 marked y. That is because it is one place in front of the other 4, making it 10 times greater. If you need any help with understand this, please let me know and I will further assist you on this question! Hope I was able to help.
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45% of 81.2 is a number between.....
Misha Larkins [42]
36.54
45% of 81.2 is 36.54.
3 0
3 years ago
What is d –10 – 2d + 7 = 8 + d – 10 – 3d
ladessa [460]

Answer:

d = 1, so 1 - 10 - 2*1 + 7 = 8 + 1 - 10 - 3*1 is true!

4 0
3 years ago
Show that f(x) f(y) - f(x+y), where f(x)= [cos x - sin x o] [sin x cos x o] [o o 1]
Naddik [55]

Answer:

The answer is below

Step-by-step explanation:

Show that f(x) f(y) = f(x+y)

From trigonometric:

sin(x + y) = sinxcosy + cosxsiny

sin(x - y) = sinxcosy - cosxsiny

cos(x + y) = cosxcosy - sinxsiny

cos(x - y) = cosxcosy + sinxsiny

f(x)=\left[\begin{array}{ccc}cosx&-sinx&0\\sinx&cosx&0\\0&0&1\end{array}\right] ,f(y)=\left[\begin{array}{ccc}cosy&-siny&0\\siny&cosy&0\\0&0&1\end{array}\right] \\\\\\f(x)f(y)=\left[\begin{array}{ccc}cosxcosy-sinxsiny&-cosxsiny-sinxcosy&0\\sinxcosy+cosxsiny&-sinxsiny+cosxcosy&0\\0&0&1\end{array}\right] \\\\\\f(x)f(y)=\left[\begin{array}{ccc}cos(x+y)&-sin(x+y)&0\\sin(x+y)&cos(x+y)&0\\0&0&1\end{array}\right] \\\\\\

f(x+y)=\left[\begin{array}{ccc}cos(x+y)&-sin(x+y)&0\\sin(x+y)&cos(x+y)&0\\0&0&1\end{array}\right] \\\\\\Therefore\ f(x)f(y)=f(x+y)

4 0
3 years ago
To find 5, Beau found 22 = 4 and 32 = 9. He said that since 5 is between 4 and 9, 5 is between 2 and 3. Beau thinks a good estim
shusha [124]

Complete question

To find \sqrt{5} , Beau found 2^2 = 4 and 3^2 = 9 . He said that since 5 is between 4 and 9, \sqrt{5}, is between 2 and 3. Beau thinks a good estimate for \sqrt{5} , is \frac{2 + 3}{2} =  2.5 Is his estimate high or low? How do you know?

Answer:

The estimation is high because 5 is very close to 4 so \sqrt{5} will also be very close to \sqrt{4} which is lower than the estimate

In order to get a good estimate

The first step is to choose a number between 2 and 3 let say 2.8 , 2,85 , 2.9 and the square them

i.e

2.1^2 =  4.41

     2.2^2 =  4.84

      2.3^2 =  5.29

From here we can see that \sqrt{5}  lies between 2.2 and 2.3 but is closer to  2.2

So a good estimate for \sqrt{5} is 2.2

Step-by-step explanation:

8 0
3 years ago
Find the y-intercept for the parabola defined by
wolverine [178]

Answer:

12

Step-by-step explanation:

Set x=0

when you do that, you will find the point where y=12 since x^2+8x=0, but adding the 12 moves up the y-component by 12 units

4 0
3 years ago
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