Slove for x mx+2nx=p

1 answer:

3 0

Solve for x.

mx+2nx=p

Factor out variable x.

x(m+2n)=p

Divide both sides by m+2n.

x(m+2n) / m+2n = p / m+2n

x=p / m+2n

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The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.26 millimeters and a standard deviat

Molodets [167]

Answer:

Top 10%: 5.35 millimeters

Bottom 10%: 5.17 millimeters

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 5.26, \sigma = 0.07$

Top 10%

X when Z has a pvalue of 1-0.1 = 0.9. So X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 5.26}{0.07}$

$X - 5.26 = 1.28*0.07$

$X = 5.35$

Bottom 10%

X when Z has a pvalue of 0.1. So X when Z = -1.28

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 5.26}{0.07}$

$X - 5.26 = -1.28*0.07$

$X = 5.17$

5 0

3 years ago

Gabby is buying flowers for a friend. She can choose daisies, carnations, or sunflowers. She can put the flowers in a clear, red

FrozenT [24]

Combination tells the number of ways an object can be arranged. The number of all of the possible combinations Gabby can have is 9.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

$^nC_r = \dfrac{n!}{r!(n-r)!}$

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of options of the flower with Gabby is 3( daisies, carnations, or sunflowers) and the color choices she has is (clear, red, or blue), therefore, she $^3C_1$ choices for the flower, also, she has $^3C_1$ choices for color.