Answer:
![\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\6&6&-19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2610%2639%5C%5C-32%26-30%26-18%5C%5C6%266%26-19%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given that A = ![\left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
and B = ![\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D)
.
Therefore, BA = × = (Answer)
For, the 1st row-1st column element is obtained by multiplying the 1st row of B matrix and 1st column of A matrix.
Similarly, the 1st row-2nd column element is obtained by multiplying the 1st row of B matrix and 2nd column of A matrix.
And so on. (Answer)
Answer:
Step-by-step explanation:
Radicals and imaginary numbers ALWAYS come in pairs when it comes to factors of polynomials. This is the called the conjugate theorem. If we are given a solution/root/zero that is
x = 3 + √5, then its conjugate is x = 3 - √5. Going backwards from the solution to the factor, we utilize the Zero Product Property and get
(x - (3 - √5)) which simplifies to (x - 3 + √5). if you are looking for the conjugate of the given zero, the choice you want is the second one down.
Subtract 7 from both sides
12 - 7 < n
Simplify 12 - 7 to 5
5 < n
Switch sides
<u>n > 5</u>
Answer:
-2x-8
Step-by-step explanation:
1) Distribute:
-6/3x+-15/3-3
2) Simplify:
-2x-5-3
3) combine like terms:
-2x-8
hope this helps
