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PtichkaEL [24]
4 years ago
12

PLEASE HELP!

Mathematics
1 answer:
777dan777 [17]4 years ago
6 0
1. 1/10 (3000) = 3000/10 = 300...so 1/10 of 3000 is 300
     300/10 = 30...and 300 is 10 times as much as 30

2. 10 times as much as 8 = (10 x 8) = 80
     1/10x = 80
      x = 80 * 10 = 800
      so 1/10 of 800 is 10 times as much as 8

3. 1/10(50,000) = 50,000/10 = 5000
    5000/10 = 500
    1/10 of 50,000 is 10 times as much as 500

4. 1/10(40,000) = 40,000/10 = 4,000
    4000/10 = 400
    1/10 of 40,000 is 10 times as much as 400

5. 1/10 (900) = 900/10 = 90
     10x = 90
      x = 90/10
      x = 9
      10 times as much as 9 is 1/10 of 900

6. 1/10 (60,000) = 60,000/10 = 6000
     10x = 6000
        x = 6000/10
        x = 600
        10 times as much as 600 is 1/10 of 60,000

7. 70 x 10 = 700
    1/10x = 700
     x = 700 * 10
     x = 7000
    10 times as much as 700 is 1/10 of 7000

8. 10 x 2000 = 20,000
    1/10x = 20,000
     x = 20,000 * 10
    x = 200,000
    10 times as much as 2000 is 1/10 of 200,000

9. 10 times as much as 2000.....2000 x 10 = 20,000
     1/10 of what is 20,000.....1/10x = 20,000....multiply both sides by 10, this      eliminates the 1/10 on the left side....resulting in 200,000.
     so basically, 10 times as much as 2000 = 20,000 and 1/10 of 200,000 =         20,000
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3 years ago
What number is 25 percent of 84?
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Insurance companies A and B each earn an annual profit that is normally distributed with the same positive mean. The standard de
krok68 [10]

Answer:

C. 0.98

Step-by-step explanation:

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P(B<0) = 0.9*P(A<0)

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7 0
3 years ago
ben earns $9 per hour and $6 for each delivery he makes. he wants to earn more than $155 in an 8-hour workday. what is the least
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First find out how much he makes in 8 hours (9x8=72). Then subtract 72 from 155 (155-72=83). Then divide 83 by 6 (83/6=13.8333). Since 83 is not evenly divisible by 6, and since he can't deliver .8333 of a delivery, we would round up, giving us 14). Ben would need to make 14 deliveries in 8 hours to make more than $155 :) Hope this helps you :)
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