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3 years ago

Which of the following equations is equivalent to the equation 6x – y = 1?A.y = 6x – 1 B.y = 6x + 1C.y = -6x + 1D.y = -6x – 1

Mathematics

2 answers:

yawa3891 [41]3 years ago

8 0

Answer:

I think the answer is:

A. y = 6x - 1

SpyIntel [72]3 years ago

5 0

I believe the answer is C.

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Answer:

4 dollars and 20 cents

Step-by-step explanation:

5.00-.80=4.20

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2 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

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Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

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2 years ago

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Ne4ueva [31]

Answer:

$33.25

Step-by-step explanation:

Taking Eric's hours as a ratio to the total hours :

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3.5 : 5.5
3.5 x 2 = : 5.5 x 2
7 : 11

Multiply the ratio into the amount paid :

52.25 x 7/11
4.75 x 7
$33.25

Eric's share of the money is $33.25

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