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cupoosta [38]
3 years ago
7

A town spends 43% of its annual budget on education.

Mathematics
2 answers:
RoseWind [281]3 years ago
8 0
430,000 dollars will be spent on education.
Aliun [14]3 years ago
7 0

Answer:

430,000 dollars will be spent on education.

Step-by-step explanation:

np

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Machines a and t were both cleaned this week machine a is cleaned every 12 weeks and machine t is cleaned every 8 weeks what is
Mice21 [21]
12x2=24 8x3=24 , so all you needed was to multiply the week until you got the same answer for both
7 0
3 years ago
Read 2 more answers
What is the answer to -4+x=5x+16
34kurt

Answer: x=-5

Step-by-step explanation:

6 0
3 years ago
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Assume the random variable X is normally distributed with mean mu equals 50 and standard deviation sigma equals 7. Compute the p
drek231 [11]

Answer:

The probability that <em>X</em> is less than 42 is 0.1271.

Step-by-step explanation:

The random variable <em>X </em>follows a Normal distribution.

The mean and standard deviation are:

E (X) = <em>μ</em> = 50.

SD (X) = <em>σ</em> = 7.

A normal distribution is continuous probability distribution.

The Normal probability distribution with mean µ and standard deviation σ is given by,

f_{X}(\mu, \sigma)=\frac{1}{\sigma\sqrt{2\pi}}e^{-(x-\mu)^{2}/2\sigma^{2}};\ -\infty

To compute the probability of a Normal random variable we first standardize the raw score.

The raw scores are standardized using the formula:

z=\frac{x-\mu}{\sigma}

These standardized scores are known as <em>z</em>-scores and they follow normal distribution with mean 0 and standard deviation 1.

Compute the probability of (X < 42) as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that <em>X</em> is less than 42 is 0.1271.

The normal curve is shown below.

6 0
3 years ago
The perimeter of a rectangular sandbox is 28ft. The length is six times the width.
VLD [36.1K]
Let the width =x
length = 6x
p=14x
28=14x
x=2
7 0
3 years ago
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

3 0
3 years ago
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