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maxonik [38]
3 years ago
5

Solve for x in the equation x squared minus 8 x + 41 = 0.

Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

x = 4 ± 5i

Step-by-step explanation:

Just use the quadratic formula (ax²+bx+c=0) like you would for every other quadratic equation. Substitute i² for -1 when you get the square root of a negative number.

a = 1

b = -8

c = 41

Solution is x = (8 ± √(64-4·41)) / 2

x = 4 ± (√-100) / 2

x = 4 ± (√-25·4)/2

x = 4 ± √-25

x = 4 ± √(25i²)

x = 4 ± 5i

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A 12.0-cm segment makes a 108.0-degree angle with a 16.0-cm segment. To the nearest tenth of a cm, find the third side of the tr
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3 years ago
Question 1 of 40<br> If f(x) = 4x² - 6 and g(x) = x² - 4x-8, find (f- g)(x).
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Answer:

\huge\boxed{\sf (f-g)(x) = 3x\² + 4x - 14}

Step-by-step explanation:

<h3><u>Given functions:</u></h3>
  • f(x) = 4x² - 6
  • g(x) = x² - 4x - 8
<h3><u>Solution:</u></h3>

Subtract both functions

(f-g)(x) = 4x² - 6 - (x² - 4x - 8)

(f-g)(x) = 4x² - 6 - x² + 4x - 8

Combine like terms

(f-g)(x) = 4x² - x² + 4x - 6 - 8

(f-g)(x) = 3x² + 4x - 14

\rule[225]{225}{2}

3 0
2 years ago
Read 2 more answers
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