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Tcecarenko [31]
3 years ago
13

If f(x)=2x-1 And g(x) =3x which statement is true

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0
I cant see any statements
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Lydia's teacher wants her class to take note of the gas prices around town and round them all to the nearest whole number. Lydia
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3.41, due to it being below .50
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3 years ago
Given a rectangle with a perimeter of 24 inches, why dimensions maximize the area?
Pepsi [2]

Answer:

The dimensions are 6 by 6

Step-by-step explanation:

Calculus answer:

2x +2y= 24

xy= A

2x=24-2y

x=12-y

(12-y)(y)= 12y- y^2

the Derivative is = 12-2y

Then set that equal to zero 0=12-2y

-12=-2y

y=6

Confirm that 6 is a maximum by using a wiggle graph

wiggle graph -∞<---inc--6---dec-->∞

6 is a maximum

plug into original equation

2x + 2(6)=24

2x+12=24

2x=12

x=6

----------------------------------------------------------------------------------------------------

y=6

x=6


     



5 0
3 years ago
You are running a fuel economy study. One of the cars you find is blue. It can travel 41 1/2 miles on 1 1/4 gasoline. Another ca
sashaice [31]

Answer:

Step-by-step explanation:

We want to study the fuel consumption of each car, i.e the amount of mile per gallon the cars will consume

Step one:

given data:

First car

distance covered= 41 1/2 = 41.5miles

amount of gallons= 1 1/4= 1.25gal

the miles per gallons= 41.5/1.25=33.2 miles per gallon

Second car

distance covered= 21 3/5= 21.6miles

amount of gallons=4/5=  0.8gal

the miles per gallons= 21.6/0.8=27 miles per gallon

1. Therefore the unit rate of

the first car = 33.2 miles per gallon

the second car=27 miles per gallon

2. the first car can travel a greater distance on 1 gallon of gasoline

8 0
3 years ago
In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9
creativ13 [48]
So...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!
4 0
3 years ago
Read 2 more answers
A blind man wanders under a door into an empty room. After running into the walls repeatedly for a while, it stops to think and
Nostrana [21]

From the side where the man is located in the 10' by 12' rectangular room, we have;

A) 0.046

B) The average time to escape in first attempt is approximately 605.02 seconds

<h3>Which concept can be used to find the odds and time of escape?</h3>

A) From The given diagram, we have;

Width of the door = 10 - 6 - 2 = 2

Therefore, the door is 2 feet wide

Distance, d1, from the man to the side of the door closer to him is given by Pythagorean theorem as follows;

  • d1 = √(6² + 7²) = √(85)

From the furthest side of the door to the man, we have;

  • d2 = √(7² + 8²) = √(113)

According to the law of cosines, we have;

2² = 85+113 - 2×√(85)×√(113) cos(A)

Where angle <em>A </em>is the angle formed by the lines from the man to the closer and farther sides of the door.

2×√(85)×√(113) cos(A) = 85+113 - 2²

A = arccos((85+113 - 2²)/(2×√(85)×√(113)))

A = arccos (194/(2×√(9605)) ≈ 8.213°

The angle of the possible directions in which the man can turn is 180°.

Therefore;

The probability, <em>P(</em><em>E)</em>, of escaping in the first move is therefore;

  • P(E) = 8.213°/180° ≈ 0.046

B) Given that the man escapes in the first move, the shortest and longest distances the man moves are;

d1 = √(85) and d2 = √(113)

Speed of the man, <em>v </em>= 0.5 cm/sec

Therefore by unit conversion function of a graphing calculator;

  • v = (25/1524) ft./sec

The times taken are;

t1 = √(85)/(25/1524) ≈ 562.023

t2 = √(113)/(25/1524) ≈ 648.014.

Average time, <em>t </em>= (t1 + t2)/2

Which gives;

t = (562.023 + 648.014)/2 ≈ 605.02

The average time it takes the man to escape in first move is <em>t </em><em>≈</em> 605.02 seconds.

Learn more about Pythagorean theorem and probability here:

brainly.com/question/27180985

brainly.com/question/654982

brainly.com/question/24756209

#SPJ1

3 0
1 year ago
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