The emf of a cell is mathematically given as
= 0.0532 v
<h3>What is the emf of a cell?</h3>
Generally, the equation for emf is mathematically given as

where,
Pb is lead
H is hydrogen
/ Pb has a standard reduction potential of -0.126 volts, while
/
has a standard reduction potential of 0.0 volts.

![[Pb^2^+] x [H^+]^2](https://tex.z-dn.net/?f=%5BPb%5E2%5E%2B%5D%20x%20%5BH%5E%2B%5D%5E2)
= 0.126 - 0.059/2 log 1 / [0.57] x [0.09]^2
= 0.0532 v
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Answer:
1.U={1,2,3,4,5}
A={2}
B={2,3}
C={4,5}
2.U={1,2,3,4}
A={1,2}
B={2,3}
C={4}
Step-by-step explanation:
We are given that
and 
are different sets
1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same
Suppose U={1,2,3,4,5}
A={2}
B={2,3}
C={4,5}

{2,3,4,5}
={2}
{2,3,4,5}={2}
={2}
={2}
Hence, 
2.We have to construct a universe set U and non empty sets A,B and C so that above sets are in fact different
Suppose U={1,2,3,4}
A={1,2}
B={2,3}
C={4}

={2,3,4}
={1,2}
={1,2}
={1,2}
{2,3,4}={2}
Hence, 
You add eight three times (8+8+8=24)
(−6,−4) would be your answer! (: