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3 years ago

What is 2.81 rounded to the nearest hundredth

Mathematics

2 answers:

nalin [4]3 years ago

8 0

$2.81$ is already rounded to the nearest hundredth and it's $0.01$ .

tresset_1 [31]3 years ago

7 0

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A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$

Plug in n = 12 and r = 9

$=\frac{12!}{9!\left(12-9\right)!}$

$=\frac{12!}{9!\cdot \:3!}$

$=\frac{12\cdot \:11\cdot \:10}{3!}$ ∵ $\frac{12!}{9!}=12\cdot \:11\cdot \:10$

$=\frac{1320}{6}$ ∵ $3!\:=\:3\times 2\times 1=6$

$=220$

Thus, the probability will be:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$=\frac{220}{4096}$

$=\frac{55}{1024}$

Thus, the probability of the coin landing tails up exactly nine times will be:

$P\left(E\right)=\frac{55}{1024}$

4 0

3 years ago

There are 36 ribbons of which 1/5 are yellow, 7/15 are pink and the remaining ribbons are

Kay [80]

Step-by-step explanation:

Let there be x blue ribbons

$\therefore \: \frac{1}{5} + \frac{7}{15} + x = 36 \\ \therefore \: \frac{1 \times 3}{5 \times 3} + \frac{7}{15} + x = 36 \\ \therefore \: \frac{3}{15} + \frac{7}{15} + x = 36 \\ \therefore \: \frac{3 + 7}{15} + x = 36 \\ \therefore \: \frac{10}{15} + x = 36 \\ \therefore \: x = 36 - \frac{10}{15} \\ \therefore \: x = \frac{36 \times 15 - 10}{15} \\ \therefore \: x = \frac{540 - 10}{15} \\ \therefore \: x = \frac{530}{15} \\ \therefore \: x = 35\frac{5}{15} \\ \\ \therefore \: x = 35\frac{1}{3} \: are \: blue. \\$

5 0

3 years ago

Help please with this question

gladu [14]

Answer:

Step-by-step explanation:

in each sample there were 50 students, in a group of 800 there would be 16 samples taken, if you divide the total amount of kids with Novemeber birthdays, 80 by the amount of samples, 16, youll learn that in each sample there are 5 students to have a birthday in november within each sample, hope this helps.

4 0

2 years ago

Read 2 more answers

Ben spent 1/6 of his money on a burger, fries, and a drink. Then he spent half of the money he had left: $5 on a magazine, $8.25

Ket [755]

The amount of money Ben had to begin with after spending 1/6 and 1/2 of it is 57 dollars.

<h3>How to find the how much money he had with an equation?</h3>

let

x = amount he had to begin with

He spent 1/6 of his money on a burger, fries, and a drink. Therefore,

amount spent on burger, fries, and a drink = 1 / 6 x

Hence,

amount he had left = x - 1 / 6 x =6x - x /6 = 5 / 6 x

Then he spent half of the money he had left.

1 / 2(5 /6 x) = 5 + 8.25 + 10.50

5 / 12 x = 23.75

cross multiply

5x = 23.75 × 12

5x = 285

divide both sides by 5

x = 285 / 5

x = 57

Therefore, the amount of money he have to begin with is $57.

learn more on equation here: brainly.com/question/5718696

4 0

2 years ago

Need help for this one!

xeze [42]

(x+3 ; y-5)

If you have (-2 ; 3) that means x = -2 and y = 3 so:

(-2+3 ; 3-5) = (1 ; -2)

5 0

3 years ago