If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Answer:
5g
Step-by-step explanation:
Answer:
It's probably it
Step-by-step explanation:
A = (-4, -2)
B = (1, 6)
Imagine a new point (C) where they intersect (1, -2)
Now we can form a triangle, the distance between A and B will be the hypotenuse.
h² = 5² + 8²
h² = 25 + 64
h² = 89
h = 
h = ~9.43...
h = 9
Given:
The descriptions and equations. The equations are


To find:
The correct description for each equation and match them.
Solution:
We know that, "+" is used for more and "×" is used for times.
Additive: y is 4 more than x.

Additive: x is 4 more than y.

Multiplicative: y is 4 times x.

Multiplicative: x is 4 times y

Therefore, the correct description for the equation
is "Multiplicative: y is 4 times x
" and the correct description for the equation
is "Additive: y is 4 more than x.
"
Answer:
48
Step-by-step explanation:
So your equation is: 5y3 - 21 + 6y2 + (25 ÷ 5) and y = 2.
Evaluate for y=2
5(23)−21+6(22)+
25
5
5(23)−21+6(22)+
25
5
=48.
So the answer is 48.