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2 years ago

If martha earns $3.25 per hour for babysitting, how much will she earn in:

Mathematics

1 answer:

Finger [1]2 years ago

7 0

$3.25 multiplied by the hour

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Suppose Paul kicks a soccer ball straight up into the air with an initial velocity of 96 feet per second. The function h(t)= -16

tangare [24]

Answer:

(d)

Step-by-step explanation:

Given

$h(t) = -16t^2 + 96t$

Required

The intercepts

The x intercepts are where the graph crosses x axis.

From the attached plot, they are:

$x = (0,0)$ and $x = (6,0)$

These represent the start and end of the ball that is launched.

Hence, (d) is true

5 0

3 years ago

Someone please help! I’ll give brainliest!!

anyanavicka [17]

Answer:

The answer is 65.97 yd^3

Step-by-step explanation:

The volume of a cone is: v = $\pi r^{2}\frac{h}{3}$

So, v = $\pi$ (3^2)(7/3) = 65.97345 yd^3

6 0

2 years ago

Can someoe help? <br> 7x-24=6x-2

just olya [345]

Answer:

$7x - 24 = 6x - 2 \\ collecting \: like \: terms \: \\ 7x - 6x = - 2 + 24 \\ 1x = 22 \\ x = \frac{22}{1} \: \: or \: \: x = 22$

6 0

2 years ago

Read 2 more answers

What rectangles below are similar? Explain why.

GrogVix [38]

What rectangles?
attach a link or pic

3 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

2 years ago