Answer: The Answer is A
Step-by-step explanation:
i think it's right
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
3.3x =29.04
to find x divide both sides by 3.3
x = 29.04 / 3.3
x = 8.8
Answer:
0.15651
Step-by-step explanation:
This can be approximated using a Poisson distribution formula.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
P(X ≤ x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to x)
where λ = mean of distribution = 20 red bags of skittles (20% of 100 bags of skittles means 20 red bags of skittles)
x = variable whose probability is required = less than 16 red bags of skittles
P(X < x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to (x-1))
P(X < 16) = Σ (e^-λ)(λˣ)/x! (Summation From x=0 to x=15)
P(X < 16) = P(X=0) + P(X=1) + P(X=2) +......+ P(X=15)
Solving this,
P(X < 16) = 0.15651
