Answer:
3p^2q^3r^2√r
Step-by-step explanation:
3√p^4q^6r^5
= 3p^2q^3r^2√r
Hope that helps
<span>What is the arc length when Θ=3 pi/5 and the radius is 7 cm?
</span><span>Here are the available answers...
21pi/5 cm
12pi/5 cm
6pi/5 cm
3pi/35 cm
</span>
Given:
arc length = theta * radius
arc length = (3 pi/5)(7cm)
arc length = 21pi/5 cm Answer is the 1st option.
<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
</span>
<h3>Answer: Approximately 6.4 units</h3>
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Explanation:
The origin is the point (0,0)
Use the distance formula to find the distance from (0, 0) to (4, -5)
Let
be our two points. Plug those values into the distance formula below and use a calculator to compute
The distance between the two points (0,0) and (4,-5) is approximately 6.4 units.
