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andriy [413]
3 years ago
15

8y + 4x + 6y=? Plz help

Mathematics
2 answers:
postnew [5]3 years ago
8 0

Answer:

idk, sorry about that one

saul85 [17]3 years ago
3 0

Answer:

14y=4x

Step-by-step explanation:

8y+4x+6y=

ok so first you get the groups like group the y's and the x's but their is no pair for the x so you leave it alone  but you add 8y+6y=14y then you put down 14y=4x

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Drag and drop the constant of proportionality into the box to match the table.
NemiM [27]

Answer: it is NOT proportional

Step-by-step explanation: it doesn’t stick to 1 number going up if that makes sense, it’s adding 1 each time it goes up but it has to stick to one number going up making this NOT proportional

4 0
3 years ago
Read 2 more answers
A recreation center charges nonmembers $3 to use the pool and $5 to use the basketball courts. A person pays $42 to use the recr
Andrei [34K]
Let x = times in the pool
Let y = times in the basketball courts

42=3x+5y
x+y=12
Therefore y = 12-x
Subsitute for y
42 = 3x + 5(12-x)
42 = 3x + 60 -5x
Subtract 60
-18 = -2x
9 = x

The person used the pool 9 times.

5 0
3 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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7 0
2 years ago
I don't understand this problem on my homework can explain to me how to solve it?
user100 [1]
So he worked 30.5 hours, he just didn't write some of the hours down. To find the hours he didn't write down, you subtract 8+7\frac14+ 8\frac12 from 30.5, which equals 6 \frac14

8 0
3 years ago
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
Read 2 more answers
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