All categories

2 years ago

What does it mean to add a negative number?

Mathematics

2 answers:

Andreas93 [3]2 years ago

5 0

Answer:

The exact same as subtracting.

Example

5 + (-2) = 3

MatroZZZ [7]2 years ago

5 0

Answer:

To add a negative number means to subtract

Step-by-step explanation:

You might be interested in

The diameter of a circle is a chord that _______ passes through the center of the circle.

SashulF [63]

The answer is A. Always.
The diameter of a circle is a line that goes from one side to the other hence passing through the center!
Hope this helped!

5 0

3 years ago

This is the problem that I need help with please. :)

Anna35 [415]

Answer:

umm I think it 186

Step-by-step explanation:

8 0

2 years ago

Sally runs 3 miles a day how far will she<br> Run in 3 days

ra1l [238]

Answer:

9 miles

Step-by-step explanation:

3 x 3 = 9 miles per day

6 0

2 years ago

Read 2 more answers

Buffalo Bill currently weighs 202 lb. He wants to weigh 180 lbs for his reunion which is 35 days from today. How many pounds per

Nostrana [21]

Answer:

He must lose 4.4 pounds per week.

Step-by-step explanation:

Buffalo Bill currently weighs 202 lb. He wants to weigh 180 lbs for his reunion.

This means that he needs to lose 202 - 180 = 22 lb.

35 days from today.

Each week has 7 days. So this is 35/7 = 5 weeks from now.

How many pounds per week must he lose?

22 pounds in 5 weeks, that is 22/5 = 4.4 pounds per week.

4 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago