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3 years ago

5

Name the special segment. HE

1 answer:

nikdorinn [45]3 years ago

4 0

Perpendicular bisector because it is perpendicular to the bottom segment (forgot what the letters were sorry lol) and also bisecting that segment
hope this helps!

You might be interested in

92% of what number is 253?

Romashka-Z-Leto [24]

Let, the number = x
Then, x * 92% = 253
x = 253 / 0.92 [ 92% = 0.92 ]
x = 275

In short, Your Answer would be 275

Hope this helps!

3 0

3 years ago

I need help.. i really want to go sleep.. thank you so much...

Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given $\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$

To verify that the above equality is true or false:

Now find $\sum\limits_{k=0}^8\frac{1}{k+3}$

Expanding the summation we get

$\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3}$ $\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Now find $\sum\limits_{i=3}^{11}\frac{1}{i}$

Expanding the summation we get

$\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Comparing the two series we get,

$\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$ so the given equality is true.

2) Given $\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}$

Verify the above equality is true or false

Now find $\sum\limits_{k=0}^4\frac{3k+3}{k+6}$

Expanding the summation we get

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}$

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}$

now find $\sum\limits_{i=1}^3\frac{3i}{i+5}$

Expanding the summation we get

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}$

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}$

Comparing the series we get that the given equality is false.

ie, $\sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}$

6 0

3 years ago

What is the minimum unit cost of C(x)=0.7^2-210x+27,464?

Vika [28.1K]

No local extrema i think?

6 0

2 years ago

Write a linear function f with the<br> values f(0) = 6 and f(4) = -6.

vagabundo [1.1K]

Answer:

f(x) = -3x + 6

Step-by-step explanation:

The general linear function is;

y = mx + b

it can also be written as (x , f(x))

f(x) = mx + b

where m is the slope and b is the y-intercept

so we have the points ;

(0,6) and (4,-6)

So we have;

for f(0) to be 6, it means that the y-intercept b is 6

This is because the value of x at the y-intercept is 0

So we have this as;

f(x) = mx + 6

Now, let’s substitute the other point so as to get m

For the other point;

x = 4 and f(x) = -6

that means;

-6 = 4m + 6

4m = -6-6

4m = -12

m = -12/4

m = -3

So we have the equation as;

f(x) = -3x + 6

3 0

3 years ago

Draw a model to show 35 1/3

katen-ka-za [31]

I think this is the answer. if not sorry

6 0

3 years ago