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3 years ago

Find the y-intercept of the parabola whose equation is f(x)=-2x^2-8x+5

Mathematics

1 answer:

tatyana61 [14]3 years ago

6 0

Answer:

i'm pretty sure the y-intercept would be 5

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PLEASE HELP ASAP

katrin [286]

Corey stepped back 59.71 feet to get a better view of the bird.

Explanation:

This is a right angled triangle. Let $\theta$ be the angle of elevation.

Let the adjacent side of the triangle be x for the angle $\theta$

Let the opposite side of the triangle by y for the angle $\theta$

Thus,

$\tan \theta=\frac{y}{x}$

Since, the height of the tree is 80 feet, $y=80$

To find the value of x, let us substitute $y=80$ and $\theta=68$

$x=\frac{80}{\tan 68^{\circ}}=32.32$

Since, Corey moves back a few steps to gain a better view of the bird, the angle of elevation is 41°

Now, we shall find the x for $y=80$ and $\theta=41$

$x=\frac{80}{\tan 41^{\circ}}=92.03$

To find how many feet Corey step back is to subtract the value of two adjacent sides, thus,

$x=92.03-32.32=59.71$

Thus, Corey stepped back 59.71 feet to get a better view of the bird.

6 0

3 years ago

How do I do that I need desperat help pls

Oksanka [162]

9 because 12 + is greater than/equal to 9+3

6 0

2 years ago

50 + 2x = 100<br> What is x?

max2010maxim [7]

Answer:

x = 25

Step-by-step explanation:

50 + 2x = 100

=> 2x = 50

=> x = 25

Hoped this helped.

4 0

2 years ago

Read 2 more answers

Find the value of x in each triangle. show your work on a separate piece of paper

motikmotik

Answer:

125

Step-by-step explanation:

all angles in a triangle add up to 180. you add 100+25=125 180-125=55 to check... 125+55=180 to angles next to each other on a straight line equals 180-55=125 angle x= 125

im pretty sure thats correct i hope this helps!

7 0

3 years ago

: If tan A=- 9/13 and 0 < A < 180, find, without using tables or calculators, the value of

stich3 [128]

Answer: $\bold{\sin A=\dfrac{9\sqrt{10}}{50}\qquad \cos A=-\dfrac{13\sqrt{10}}{50}}$

<u>Step-by-step explanation:</u>

0° < A < 180° so it is in Quadrant I or II

since tan A is negative, it is in Quadrant II ---> (-x, +y)

$\text{Given}:\tan A=\dfrac{y}{x}\ =\dfrac{9}{-13}$

Next, find the hypotenuse given that x = -13 and y = 9

(-13)² + (9)² = r²

250 = r²

5√10 = r

$\sin A = \dfrac{y}{r}\quad =\dfrac{9}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{\dfrac{9\sqrt{10}}{50}}\\\\\\\\\cos A = \dfrac{x}{r}\quad =\dfrac{-13}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{-\dfrac{13\sqrt{10}}{50}}$

8 0

3 years ago