3 years ago

Find the y-intercept of the parabola whose equation is f(x)=-2x^2-8x+5

Mathematics

1 answer:

tatyana61 [14]3 years ago

6 0

Answer:

i'm pretty sure the y-intercept would be 5

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If 25% of a number is 20, what is 60% of the number

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3 years ago

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trapecia [35]

Answer:

Is here a pic that goes with it?

Step-by-step explanation:

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3 years ago

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

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3 years ago

From an airplane flying over the ocean, the angle of depression to a submarine lying under the surface if 24 degrees 10 minutes.

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I think is 10 m/ s per sec

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3 years ago

Answer this question step by step

KiRa [710]

I hope this help you

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3 years ago