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Taya2010 [7]
3 years ago
10

Find the y-intercept of the parabola whose equation is f(x)=-2x^2-8x+5

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0

Answer:

i'm pretty sure the y-intercept would be 5

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13/4 =12/4 +1/4=3+1/4 so it has to be between 3 and 4 on the number line.Hope this helps and thank you for letting me help you ✅
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Write 894,217 in expended form an using number names
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Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

3 0
3 years ago
Pam wants to buy a DVD player. The original price is $50. What is the sale price? with a 90% off
qaws [65]

Answer:

5 dollars

Step-by-step explanation:

If the price is 90 % off, we will pay 100 - 90 or 10 %

Take the original price times 10 %

50 * 10 %

50 * .10

5

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3 years ago
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