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3 years ago

2 (4x - 8) + 16t = 48

1 answer:

8 0

Distributive property first so you wanna do 2•4 then you will get 8x then you have to do 2•8 Wich is 16 then you will end up with 8x-16+16t=48 move the expression to the right 8x=48+16-16t 8x=64-16t x=8-2t?

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Are the graphs of the lines in the pair parallel? Explain.<br><br> y = 4x – 4<br> 24x – 4y = 96

Radda [10]

Answer:

They are not parallel.

Put the equation in y=mx=b format to compare. The first equation (y=4x-4) is already in the right format.

If m (slope) is the same, then the lines are parallel.

-4y=96-24x

/-4 all sides

y= - 24+ 6x

y=6x-24

y=4x-4

6 is not equal to 4, slopes are not the same. Not parallel.

6 0

4 years ago

Please help and thank you

ICE Princess25 [194]

Answer:

Step-by-step explanation:

15/3=5

5 x 5 = 25

25 + 5 = 30

4 0

3 years ago

Read 2 more answers

I NEED HELPPPPPP It’s about constant rate I DONT GET THIS AT ALL :’( Explanation needed PLEASEEEEEEEE

Vika [28.1K]

Answer:

D Antenna #4

Step-by-step explanation:

As per given graph we can write the function

the intercept is zero, as x=0, y=0

at x=2, y=30 ⇒ 30= 2*15
at x=4, y=60 ⇒ 60= 4*15

The slope is 15, so the function is

y=15x

And the function for the antenna revolving at twice the rate would be

y=30x

Comparing data in given tables we can see it is D Antenna #4

x= 22 ⇒ y= 22*30= 660
x=24 ⇒ y= 24*30= 720

7 0

3 years ago

We would like to use the power series method to find the general solution to the differential equation d 2y dx2 − 4x dy dx + 12y

Feliz [49]

$y=\displaystyle\sum_{n\ge0}a_nx^n$

$\dfrac{\mathrm dy}{\mathrm dx}=\displaystyle\sum_{n\ge1}na_nx^{n-1}\implies4x\dfrac{\mathrm dy}{\mathrm dx}=4\sum_{n\ge1}na_nx^n=4\sum_{n\ge0}na_nx^n$

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}=\sum_{n\ge0}(n+2)(n+1)a_{n+2}x^n$

Substituting into the ODE

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-4x\dfrac{\mathrm dy}{\mathrm dx}+12y=0$

gives

$\displaystyle\sum_{n\ge0}\bigg((n+2)(n+1)a_{n+2}-4na_n+12a_n\bigg)x^n=0$

so that the coefficients of the series are given according to

$\begin{cases}a_0=y(0)\\a_1=y'(0)\\a_{n+2}=\dfrac{4(n-3)a_n}{(n+2)(n+1)}&\text{for }n\ge0\end{cases}$

We can shift the index in the recursive part of this definition to get

$a_n=\dfrac{4(n-5)a_{n-2}}{n(n-1)}$

for $n\ge2$ . There's dependency between coefficients that are 2 indices apart, so we can consider 2 cases:

If $n=2k$ , where $k\ge0$ is an integer, then

$k=0\implies n=0\implies a_0=a_0$

but since $y(0)=0$ , we have $a_0=0$ and $a_{2k}=0$ for all $k\ge0$ .

If $n=2k+1$ , then

$k=0\implies n=1\implies a_1=a_1$

$k=1\implies n=3\implies a_3=\dfrac{4(-2)a_1}{3\cdot2}=-\dfrac43a_1$

$k=2\implies n=5\implies a_5=0$

and so $a_{2k+1}=0$ for all $k\ge2$ . If $y'(0)=1$ , we then have $a_1=1$ and $a_3=-\dfrac43$ .

So the ODE has solution

$y(x)=\displaystyle\sum_{k\ge0}(a_{2k}x^{2k}+a_{2k+1}x^{2k+1})\implies\boxed{y(x)=x-\dfrac43x^3}$

8 0

3 years ago

Help plz (filling 20 characters)

Aleonysh [2.5K]

For number one, you’re decimal is technically after zero. To change your percentage into a real decimal number, move the decimal twice to the left. Then you will get 3.5. 3.5 is also equivalent to 3 1/2. Do the same for numbers 23 and four. For number five, each you need to know that each hole number represents 100%. If you do the math you will realize that 1/2 equals 50%. When you add them together, you get 250%. Do the same for Numbers six, seven, and eight.

7 0

4 years ago