Plz help me and the 3rd word/number is 19 if u didn't know

PERSONAL EXEMPTIONS

WINSTONCH [101]

5151.56 - 3000 = 2151.56

5 0

2 years ago

Another landscape architect recommends installing a triangular statue

Dima020 [189]

Answer:

A landscape architect recommends installing a triangular statue with

vertices at (10, −10), (10, −8), and (7, −10).

a. Is the triangle congruent to triangle T ? Justify your answer.

b. Propose a series of rigid motions that justifies your answer to part a.

6. Another landscape architect recommends installing a triangular statue

Step-by-step explanation:A landscape architect recommends installing a triangular statue with

vertices at (10, −10), (10, −8), and (7, −10).

a. Is the triangle congruent to triangle T ? Justify your answer.

b. Propose a series of rigid motions that justifies your answer to part a.

6. Another landscape architect recommends installing a triangular statue

5 0

2 years ago

Solve the system equations. <br> X+2y=0<br> 10y=-5

nexus9112 [7]

Answer:

x=1

y=-1/2

Step-by-step explanation:

x+2y=0....(1)

10y=-5.....(2)

From (2) we can find y.

y=-5/10

y=-1/2

Use that in (1)

x+2*(-1/2)=0

x-1=0

x=1

5 0

2 years ago

in a 30°-60°-90° triangle, the ( blank) is the (blank) the length of the ( blank) while the longer leg is ( blank) times the len

levacccp [35]

Answer:

16

Step-by-step explanation:

4 0

2 years ago

vDetermine if a Poisson experiment is described, and select the best answer: Suppose we knew that the average number of typos in

goldenfox [79]

Answer:

probability that a randomly selected page that contains only text will contain no typos that is

P(x=0) = $e^{-0.08}$ = 0.923

Step-by-step explanation:

<u>Poisson distribution</u>:-

Explanation of the Poisson distribution :-

The Poisson distribution can be derived as a limiting case of the binomial

distribution under the conditions that

i) p is very small

ii) n is very large

ii) λ = np (say finite

The probability of 'r' successes = $\frac{e^{-\alpha }\alpha^r }{r!}$

Given the average number of typos ∝ = 0.08 per page.

probability that a randomly selected page that contains only text will contain no typos that is = $p(x=0) = \frac{e^{-0.08 }\(-0.08)^0 }{0!}$

After calculation P(x=0) = $e^{-0.08}$ = 0.923

probability that a randomly selected page that contains only text will contain no typos =0.923

5 0

2 years ago