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dangina [55]
3 years ago
13

Three of these methods gives the correct area of the figure. Which method does NOT?

Mathematics
1 answer:
maw [93]3 years ago
8 0

Ah hah !  NOW I see it.  Thanks to BellBell for a good link.

My first impression is a dog bone standing up on one end.

You're talking about the area of the figure, so I'll think that over
before I look at the choices.

I see:

-- 2 semi-circles = 1 whole circle.
and
-- (1 rectangle) minus (a trapezoid).

Now I'll look through the choices.

A).  No good.  The trapezoid is cut OUT of the figure,
and shouldn't be added into it.

B).  Oh ! Yes !  I didn't look at it that way at first, but
I can see how that works.  'B' is good.

C). and D).  Yes.  This was my description above.

So 'A' is the method that's wrong.

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First, rewrite 14/25 and 11/20 so that they have a common denominator. Then, use <, =, >
muminat

Answer: 14/25 = 56/100

               11/20 =  55/100

               14/25 > 11/20

Step-by-step explanation:

The least common multiple of 20 and 25 is 100.

(100 = 20*5, 25*4)

So we can take the common denominator 100.

14*4/25*4 =56/100. ∴14/25 = 56/100

11*5/20*5  =55/100. ∴11/20  = 55/100

56>55

∴56/100 > 55/100

∴14/25 > 11/20

Hope it's good;)

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3 0
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Read 2 more answers
2nd question :) please help quick
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Answer:

look id k which ans u want I m telling both

#5 such number could be <em><u>0</u></em> becoz it is not whole integer or positive

#6 there could be many numbers like

8.67676767.....

or

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