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2 years ago

The list 11, 20, 31, 51, 82 is an example of a list of five strictly positive integers

Mathematics

1 answer:

Xelga [282]2 years ago

8 0

Zero integers will be 124 the closet you can get is 123

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3(2x + 11) and (3x + 15)(2)

algol [13]

Answer:

3(2x+11)= 6x+33 and (3x+15)(2) = 6x+30

Step-by-step explanation:

Use distributive property to multiply the outside factor to each factor inside the parenthesis.

3(2x+11)

(3*2x)+(3*11)

6x+33

3 0

3 years ago

Help please!!! A bag contains 50 marbles, 10 of which are blue, 8 are red, 20 are green, and 12 are purple. Marcie takes a marbl

Andru [333]

Answer:

Step-by-step explanation:

We would need to multiply the number of trials (which is 500) by the probability of choosing a red in 1 try from the information given.

There are 50 in total, and 8 of them are red, so:

P(red) = $\frac{8}{50}=0.16$

Now we multiply this with 500 to get:

$500*0.16=80$

The correct answer is A.

5 0

3 years ago

Read 2 more answers

Mindy and Troy combined ate 9 99 pieces of the wedding cake. Mindy ate 3 33 pieces of cake and Troy had 1 4 4 1 start fraction

saul85 [17]

Answer:

(a)There are 24 cakes in total

(b)There are 15 pieces of cakes left

Step-by-step explanation:

Let the total cakes=x

Let number of cakes eaten by Mindy=m

Let number of cakes eaten by Troy=t

Now:

m=3

Since m+t=9

3+t=9

t=9-3=6

The Number of Pieces of Cake Left in Total=x-(t+m)

Since Troy had $\frac{1}{4}$ of the total cake

$\frac{1}{4} of x=6$

$\frac{1}{4} X x=6$

x=6X4=24

(a)There are 24 cakes in total

(b)The Number of Pieces of Cake Left in Total=x-(t+m)=24-9=15 cakes

5 0

3 years ago

6. Write the equation of the line in slope-intercept form that has the following points: (1, -3) (0, -5)

Troyanec [42]

Answer:

y = 2x −5

Step-by-step explanation:

The slope is 2 and the Y intercept is -5 so the equation is:

y = 2x -5

7 0

2 years ago

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is -10.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is -10.

3 0

3 years ago