The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
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Answer:
OK midpoint is actually really easy I got u
Step-by-step explanation:
X2+X1 divided by 2
Y2+Y1 divided by 2
7+-1/2 is 6.5
-1+3/2 is 0.5
(6.5,0.5)
Answer:
C: y=11x
Step-by-step explanation:
11x2=22
11x3=33
11x4=44
So on and so forth.
