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Paladinen [302]

2 years ago

15

Find two consecutive whole numbers that the square root of 47 lies between.

1 answer:

ella [17]2 years ago

3 0

$\sqrt{47}\approx6.9$

So those two consecutive whole numbers will be 6 and 7.

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35% of what number is 84 ?

satela [25.4K]

Answer:

29.4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

In each case use the new theorems to arrange the letters measures from greatest to least

tino4ka555 [31]

Answer:

answer is a,b,c

Step-by-step explanation:

7 0

2 years ago

A toothbrush and toothpaste cost one dollar and ten cents total. The toothbrush costs a dollar more than the toothpaste. How muc

Aleks [24]

Cost of the toothbrush and the toothpaste together = $1.10
Let us assume the cost of the toothpaste = x
Then
The cost of the toothbrush is = (x + 1) dollar
Then we can write the equation as
x + x+ 1 = 1.10
2x + 1 = 1.10
2x = 1.10 - 1
2x = 0.10
x = 0.10/2
= .05 dollars
So the cost of the toothpaste is 0.05 dollars.<span>I hope the procedure is clear to you.</span>

5 0

2 years ago

If an = 2n - 8, then which one is not a term of the sequence? ( an means nth term)

Phantasy [73]

Answer:

13 is answer

Step-by-step explanation:

hope it helps

3 0

2 years ago

3. The sum of the second term and the ninth term of an arithmetic sequence is -5. The sum of the third and fourth terms of the s

GaryK [48]

Answer:

First term of the sequence is $11$

Step-by-step explanation:

Let $a$ be the first term and $d$ be the common difference

We have

The sum of the second term and the ninth term of an arithmetic sequence is $-5$

$a+(2-1)d+a+(9-1)d=-5\\\\2a+9d=-5---eqn1$

The sum of the third and fourth terms of the same sequence is $7$

$a+(3-1)d+a+(4-1)d=7\\\\2a+5d=7---eqn2$

eqn 1 - eq2

$4d=-12\\\\d=-3$

Substituting in eqn 1

$2a+9\times -3=-5\\\\2a=22\\\\a=11$

First term of the sequence is $11$

4 0

2 years ago