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Paladinen [302]
3 years ago
15

Find two consecutive whole numbers that the square root of 47 lies between.

Mathematics
1 answer:
ella [17]3 years ago
3 0
\sqrt{47}\approx6.9

So those two consecutive whole numbers will be 6 and 7.
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Which graph shows y &lt; x² +1?<br> O<br> 4) Intro<br> •
Ket [755]

The graph at option 1 shows the given inequality y < x² + 1. The domain and range of the given inequality is {x: x ∈ (-∞, ∞)} and {y: y ∈ [1, ∞)}.

<h3>How to graph an inequality?</h3>

The steps to graph an inequality equation are:

  • Solve for the variable y in the given equation
  • Graph the boundary line for the inequality
  • Shade the region that satisfies the inequality.

<h3>Calculation:</h3>

The given inequality is y < x² + 1

Finding points to graph the boundary line by taking y = x² + 1:

When x = -2,

y = (-2)² + 1 = 4 + 1 = 5

⇒ (-2, 5)

When x = -1,

y = (-1)² + 1 = 2

⇒ (-1, 2)

When x = 0,

y = (0)² + 1 = 1

⇒ (0, 1)

When x = 1,

y = (1)² + 1 = 2

⇒ (1, 2)

When x = 2,

y = (2)² + 1 = 5

⇒ (2, 5)

Plotting these points in the graph forms an upward-facing parabola.

So, all the points above the vertex of the parabola satisfy the given inequality. Thus, that part is shaded.

From this, the graph at option 1 is the required graph for the inequality y < x² + 1. The boundary line is dashed since the inequality symbol is " < ".

Learn more about graphing inequalities here:

brainly.com/question/371134

#SPJ1

5 0
2 years ago
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How do you write a song that will knock over a cow
sergeinik [125]
Is this really a school question or is it just you being weird?
6 0
3 years ago
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Can anyone help please?
stepladder [879]

Answer:

h(t) = -16t(t-6)

h(2) = 128

Step-by-step explanation:

h(t) = -16t² + 96t

h(t) = -16t(t-6)

t = 3

h(2) = -16(2)(2 - 6)

h(2) = 128

7 0
3 years ago
87°
Tresset [83]
B.59
Explanation: the interior angles of a triangle equal 180.
5 0
3 years ago
What is the inverse of A(r)=15+3r
mel-nik [20]

Answer:

A(r)=15-3r

Step-by-step explanation:

switch the sign of +3r to make it -3r

5 0
3 years ago
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