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4 years ago

What is P(A and B)?

Mathematics

2 answers:

Wittaler [7]4 years ago

6 0

Answer: the fraction 3/7

=====================================================

Explanation:

We have 7 places: India, Tokyo, Houston, Peru, New York, Tijuana, Canada

Out of these 7 places, 3 of them are both a city and in North America. Those three places are: Houston, New York, Tijuana

We divide the two values (smaller over larger) to get the final answer 3/7

writing P(A and B) is shorthand for asking for the probability of getting a city AND that place is also in north america as well.

Amiraneli [1.4K]4 years ago

6 0

Answer is 3/7 hope it helps

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Answer:

Which set of side lengths is a Pythagorean triple? 9, 40, 41

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9 = a

40 = b

41 = c

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4 years ago

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1. This is one confusing question... But here is what I did
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3 years ago

At the city museum, child admission is $5.60 and adult admission is $9.20. On Sunday, 145 tickets were sold for a total sales of

Studentka2010 [4]

Let x be the number of child admission tickets sold:
Child's ticket = x

There is a total of 145 tickets sold:
Adult = 145 - x

Total sales is $1020.80:
5.6x + 9.2(145 - x) = 1020.8

Solve for x:
5.6x + 9.2(145 - x) = 1020.8
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4 years ago

Read 2 more answers

There are three modes of transporting material from Ontario to Florida, namely, by land, sea, or air. Also land transportation m

Semenov [28]

Answer:

0.057

0.6140

0.3158

0.0701

Step-by-step explanation:

Given that:

Let :

P(L) = Number transported by land = half = 50% = 0.5

P(S) = number transported by sea = 30% = 0.3

P(A) = Number transported by air = (100 - (50 + 30))% = 20% = 0.2

P(H) = highway transport = 40% of land transport = 0.4 * 0.5 = 0.2

P(R) = Rail shipment =(100- 40)% = 60% of land transport = 0.6 * 0.5 = 0.3

Percentage of damaged cargo :

Let probability of damage = P(d)

P(d | H) = 0.1

P(d | R) = 0.05

P(d | S) = 0.06

P(d | A) = 0.02

1) What percentage of all cargoes may be expected to be damaged

[P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2) = 0.057

(2) If a damaged cargo is received, what is the probability that it was shipped by ;

land?

((0.1*0.2) + (0.05*0.3)) / (0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2)

= 0.035 / 0.057

= 0.6140

By sea?

(0.06 * 0.3) / 0.057

= 0.3158

By air?

(0.02 * 0.2) / 0.057

= 0.0701

7 0

3 years ago